How to fix my for loop to continue to the next value in the list when condition is false?

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Amanda S 2020-7-6

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评论： Amanda S 2020-7-7

Hi,

Could anyone help me with how I could fix my code so it continues to check the next value in the list (Besparingslistan) if the condition in the IF-statement is false?

Also, right now I get the error "Index exceeds the number of array elements (13)." How can I fix it?

(The "Besparingslistan" is a list with the size 169x3 built up with different combinations of 13 different customers in the first two columns and a savingsvalue in the third column. While Kund_i_tur and Turkonfig are column vectors with the customers, aka (1:1:13). )

f = size(Besparingslistan,1);
a = size(Besparingslistan,2);
for forstatur = 1:f
    for andratur = 1:a
        if Kund_i_tur(f)~= Kund_i_tur(a)
           Turkonfig = {f a};
        end
    end
end   

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Image Analyst 2020-7-6

在 MATLAB Online 中打开

What does this show in the command window:

whos Besparingslistan
whos Kund_i_tur

It seems like either (the poorly named) f or a is larger than the length of Kund_i_tur.

Amanda S 2020-7-7

It says:

>> whos Besparingslistan

whos Kund_i_tur

Name Size Bytes Class Attributes

Besparingslistan 169x3 4056 double

Name Size Bytes Class Attributes

Kund_i_tur 13x1 104 double

And i understand that the varibles are different sizes but I dont know how to do it any other way since I want to loop through Besparingslistan with "forstakund" as row i column 1 and "andrakund" as row i column 2. forstakund and andrakund are supposed to change value as the loop iterations goes forward.

Kund_i_tur is supposed to represent a vector that eventually will be updated and show which routes that the customers 1-13 is part of (the whole code is based on the Clarke & Wright savings algoritm), therefore I dont know how to do it another way...

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