Working with for loop

Question

Tania Islam 2020-7-6

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/560273-working-with-for-loop

评论： Tania Islam 2020-7-7

Hi,

In my following code I want my final result ( final_delay) without skipping any index. Currently it skipping 4 index because of this line (i_value= 1:4:len). But I dont want to skip this index for my final result. How can I do that.

Thank you so much for your time and considerations.

data1=rand(1,1000)
data2=rand(1,1000)
data3=rand(1,1000)
len=200;
time=zeros(1,len)
trigger=3
for i_value= 1:4:len
       delay1=data1(i_value)
       delay2=data1(i_value+1)
      delay_1=(delay1+delay2)/2 
       delay3=data2(i_value)
       delay4=data2(i_value+1)
       delay_2=(delay3+delay4)/2
       RTT_1=data2(i_value+2)+data3(i_value)+data1(i_value+2)
       final_delay(i_value)=  abs(RTT_1-delay_1-delay_2)        
end

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madhan ravi 2020-7-6

Yet again you forgot to attach how the expected result should look like. Paste it as a text , screenshot is not useful.

Tania Islam 2020-7-6

Thank you so much for your time to consider this problem. I think I am close to my answer by @Matt J.

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Answer 1

Matt J 2020-7-6

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/560273-working-with-for-loop#answer_461666

编辑：Matt J 2020-7-6

在 MATLAB Online 中打开

I_values=1:4:len;
final_delay=nan(1,numel(I_values)); %PRE-ALLOCATE!!!!!!
for k=1:numel(I_values)
    
       i_value=I_values(k);% Matt J inserted
    
           delay1=data1(i_value)
           delay2=data1(i_value+1)
           delay_1=(delay1+delay2)/2 
           delay3=data2(i_value)
           delay4=data2(i_value+1)
           delay_2=(delay3+delay4)/2
           RTT_1=data2(i_value+2)+data3(i_value)+data1(i_value+2)
       
       final_delay(k)=  abs(RTT_1-delay_1-delay_2)  %Matt J edited        
end
   