Product of probabilities by group

2 次查看(过去 30 天)
Hi,
I have matrix that contains in the first column a group identifier and in the second column a probability. I want to generate, for each group identifier, the product of the probabilities that correspond to that group.
For example
X=[1 0.5;1 0.3; 1 0.4; 2 0.7; 2 0.4];
What I want is to generate a matrix
Y=[1 (0.5*0.3*0.4);2 (0.7*0.4)];
and I can't do it "by hand" because the number of groups and the number of probabilities is huge.
Any ideas? Thanks.

采纳的回答

Matt Fig
Matt Fig 2012-12-8
编辑:Matt Fig 2012-12-8
Here is another method. This might work best if you have groups in increments of one because it uses the group number as the index of the return array.
Y = accumarray(X(:,1),X(:,2),[],@prod);
Y(I) is the product of the probabilities belonging to the Ith group. To understand this, look at:
X = [1 0.5000
1 0.3000
1 0.4000
2 0.7000
4 0.5000
4 0.6000
6 0.7000
6 0.2000]; % No group 3 or 5.
Y = accumarray(X(:,1),X(:,2),[],@prod);
Since there is no group 3 or 5 in X, Y(3) and Y(5) are zero. If there are missing groups in your array, you can still get to the desired form like:
Z = [find(Y),Y(Y~=0)];

更多回答(2 个)

the cyclist
the cyclist 2012-12-8
Here's one way:
[uniqueX1,~,index] = unique(X(:,1));
numberUniqueX1 = numel(uniqueX1);
Y = nan(numberUniqueX1,1);
for nx = 1:numberUniqueX1
Y(nx) = prod(X(index==nx,2));
end

Fernando
Fernando 2012-12-8
Thanks for your help!

类别

Help CenterFile Exchange 中查找有关 Creating and Concatenating Matrices 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by