Info

此问题已关闭。 请重新打开它进行编辑或回答。

for loop for t

3 次查看(过去 30 天)
Ali
Ali 2020-7-7
关闭: MATLAB Answer Bot 2021-8-20
t=0.75
a1=2*t*x/(1+t)+t+k;
ad=t/a1;
ap=k/a1;
p(1)=1.01325*10^5;
for i=1:14;
p(i+1)=p(i)+20000;
end
sd=(Ad*p)/(2*rho*g*Veo);
sp=(Ap*p)/(2*rho*g*Vco);
kdd=sd*(ad-q*keb);
kdp=sd*ap;
kpp=sd*o*(q*kcb+ap);
kpd=sd*o*ad;
B=[1];
B(1:15)=B;
C=2*(rw*ep+ed);
C(1:15)=C;
D=(1-kdd)+(rw^2+kpp)+4*rw*ep*ed;
E=2*ed*(rw^2+kpp)+rw*ep*(1-kdd);
F=(rw^2+kpp).*(1-kdd)+kpd.*kdp;
B=B';
C=C';
D=D';
E=E';
F=F';
w=[B C D E F];
[m,n] = size(w) ;
r = zeros(m,n-1) ;
for i = 1:m
r(i,:)= roots(w(i,:))
end
r=real(r)
r=unique(r)
  4 个评论
Aquatris
Aquatris 2020-7-7
what is the question?
Image Analyst
Image Analyst 2020-7-7
No question, just an announcement.
I tried to run it but after entering random numbers for lots of missing variables, I finally gave up. It's pretty clear that Ali never read the links Rik sent.

回答(0 个)

此问题已关闭。

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by