Third Order Boundary Value Problem (BVP) with Boundary Coditions only in Terms of Derivatives
1 次查看(过去 30 天)
显示 更早的评论
I need to solve the boundary value problem (related to flow of fluids in conical ducts):
Y''' + 1 - Y'^2 = 0
with all the three BCs bing only on the derivatives of Y (and none on Y itself):
Y'(0)=Y"(inf)=0
Y'(inf)=1
By formulating the problem exactly as suggested here:
dYdX = @(X,Y) [Y(2); Y(3); Y(2).^2-1]; % Differential equation
res = @(ya,yb) [ya(2); yb(3); yb(2)-1];
SolYinit = bvpinit([0 5], [0; 0; 0]);
Fsol = bvp4c(dYdX, res, SolYinit);
X = Fsol.x;
Y = Fsol.y;
I tried to solve the problem, but received the Jacobian error.
Is it possible that the error is generated because the BCs do not contain Y(...), and is there a way around his problem?
4 个评论
darova
2020-7-8
I mean this
Y'(0)=Y"(inf)=0
Y'(inf)=1
res = @(ya,yb) [ya(2); yb(3); yb(2)-1];
THere are only derivatives. There should be at least one Y(0) or Y(inf) (starting or final position)
回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Boundary Value Problems 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!