Programmatically define elements of a matrix

2020 7 7
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更新时间：2020 7 8
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I have the following code:
cellnumber=6;
Vtype=4;
r=500;
H=500;
d=0.5*r;
nodes = [0 0 r 0 -r 0 sqrt(2)*r/2 -sqrt(2)*r/2 -sqrt(2)*r/2 sqrt(2)*r/2
0 0 0 r 0 -r sqrt(2)*r/2 sqrt(2)*r/2 -sqrt(2)*r/2 -sqrt(2)*r/2
H-d H 0 0 0 0 2*H-d 2*H-d 2*H-d 2*H-d];
totalnodes=size(nodes,2)+(cellnumber-1)*(size(nodes,2)-Vtype);
nodestotal=zeros(3,totalnodes);
for i=1:size(nodes,2)
nodestotal(:,i)=nodes(:,i);
for ii=size(nodes,2)+1:size(nodes,2)-Vtype:totalnodes
nodestotal(1,ii)=nodes(1,1);
nodestotal(2,ii)=nodes(2,1);
nodestotal(3,ii)=?????????;
for jj=size(nodes,2)+2:size(nodes,2)-Vtype:totalnodes
nodestotal(1,jj)=nodes(1,2);
nodestotal(2,jj)=nodes(2,2);
nodestotal(3,jj)=?????????;
end
end
end
I would like to assign specific values to specific elements of nodestotal (indicated as ?????????) in for loop. In particular such values are:
nodestotal(3,11)=3*H-2*d nodestotal(3,12)=3*H-*d
nodestotal(3,17)=5*H-3*d nodestotal(3,18)=5*H-2*d
nodestotal(3,23)=7*H-4*d nodestotal(3,24)=7*H-3*d
nodestotal(3,29)=9*H-5*d nodestotal(3,30)=9*H-4*d
nodestotal(3,35)=11*H-6*d nodestotal(3,36)=11*H-5*d
How can I do this?
Notice that cellnumber can vary.

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 采纳的回答

Gaetano Pavone
Gaetano Pavone 2020-7-8

0 个投票

This is the solution:
for i=1:size(nodes,2)
nodestotal(:,i)=nodes(:,i);
index1=(size(nodes,2)+1:size(nodes,2)-Vtype:totalnodes);
index2=(size(nodes,2)+2:size(nodes,2)-Vtype:totalnodes);
for ii=size(nodes,2)+1:size(nodes,2)-Vtype:totalnodes
nodestotal(1,ii)=nodes(1,1);
nodestotal(2,ii)=nodes(2,1);
idx1=find(index1==ii);
nodestotal(3,ii)=((2*idx1)+1)*H-(idx1+1)*d;
for jj=size(nodes,2)+2:size(nodes,2)-Vtype:totalnodes
nodestotal(1,jj)=nodes(1,2);
nodestotal(2,jj)=nodes(2,2);
idx2=find(index2==jj);
nodestotal(3,jj)=((2*idx2)+1)*H-idx2*d;
end
end
end

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