my own imhist function error

3 次查看（过去 30 天）
Ana
Ana 2012-12-10
Hello, iam new in matlab, and i have some questions about this function i made. my teacher wants us to do our own imhist, and i did this. my question is, iam using a double image and it gives an error, what i should change in this function to works fine with double image.
( Attempted to access vetor(1.01519); index must be a positive integer or logical.)
function img2 = HistOnMyOwn(image)
%UNTITLED2 Summary of this function goes here
% Detailed explanation goes here
img2=image;
im2double(img2);
vetor=zeros(256,1);
for i=1:size(img2,1)
for j =1:size(img2,2)
vetor(img2(i,j)+1) = vetor(img2(i,j)+1)+1;
end
end
plot(vetor);
end

请先登录，再回答此问题。

采纳的回答

Sean de Wolski
Sean de Wolski 2012-12-10
This oughtta make it pretty clear:
im2double(uint8(1:10:255))

更多回答（1 个）

Image Analyst
Image Analyst 2012-12-10
DO NOT use image as the name of your input argument - you'd be blowing away the important built-in image() function.
Your
im2double(img2);
line does nothing since it's not assigned to anything. Even if it did, it would do nothing because your image is apparently already a double in the range 0-1. You should do this instead:
img2 = uint8(255 * inputImage); % Using inputImage here instead of image.
Note: if your double image has values outside the 0-1 range, then you'll have to do things a little differently.
  3 个评论
显示 1更早的评论
Image Analyst
Image Analyst 2012-12-10
So img2(i,j)+1 is 1.05098???? I just don't see how img2(i,j) can possibly have the value 0.05098 when you multiplied it by 255 and rounded it to the nearest integer. It just doesn't make sense. It must be an integer in the range 0-255. Is there some code you're not sharing? Put this line inside your inner most for loop
fprintf('(i, j) = (%d, %d), img2(%d, %d) = %d\n',...
i, j, i, j, img2(i, j);
Tell me what you discover.
Image Analyst
Image Analyst 2012-12-10
Hmmmm. You just accepted Sean's answer. Ok, I guess whatever the problem was, you finally figured it out.

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Image Category Classification 的更多信息

标签

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by