ploting a function handle

can someone help me out please. I'm trying to plot this code but it gives me some errors ı don't know how to solve. It's my first time to use handle function.
close all;
clear variables;
clc;
f =1:0.1:28;
SF=4.0;
d0=1;
c = 3e8;
h_BS = 15;
TRDistance= 20;
h_BS = 15;
TRDistance= 20;
TXPower=30;
lambda = @(f) (c/(f*1e9));
PL_dB = @(f)(20*log(4*pi*d0*f*1e9/c) + 23.1*(1-0.03*((h_BS-35)/35))*log((TRDistance)) + SF*randn);
Pr_dBm =@(f)( TXPower - PL_dB);
figure;
plot(f, Pr_dBm(f));
xlabel('f');
ylabel('Pr_dBm');

 采纳的回答

madhan ravi
madhan ravi 2020-7-10
编辑:madhan ravi 2020-7-10
SF=4.0;
d0=1;
c = 3e8;
h_BS = 15;
TRDistance= 20;
TXPower=30;
lambda = @(f) (c/(f*1e9));
PL_dB = @(f)(20*log(4*pi*d0*f*1e9/c) + 23.1*(1-0.03*((h_BS-35)/35))*log((TRDistance)) + SF*randn);
Pr_dBm =@(f) TXPower - PL_dB(f);
figure(1)
fplot(Pr_dBm, [1,28])
xlabel('f')
ylabel('Pr_dBm')

更多回答(1 个)

You are trying to subtract a variable with a function handle
Pr_dBm =@(f)( TXPower - PL_dB);
You should evaluate the function. This might work
Pr_dBm =@(f)( TXPower - PL_dB(f));

类别

帮助中心File Exchange 中查找有关 Interactive Control and Callbacks 的更多信息

产品

版本

R2013a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by