given that you have this line of code how do you count the number of points in each quadrant ?

1 次查看(过去 30 天)
Classical = pdist2(matrix_logdiff_nsample, mean(matrix_logdiff_nsample),'mahal');
p = size(matrix_logdiff_nsample,2);
chi2quantile = chi2inv(0.99,p);
[SFmcd, MFmcd, Fmcd, OutFmcd] = robustcov(matrix_logdiff_nsample);
plot(Classical, Fmcd, 'o')
line([chi2quantile, chi2quantile], [0, 120], 'color', 'r')
line([0, 80], [chi2quantile, chi2quantile], 'color', 'r')
hold on
plot(Classical(OutFmcd), Fmcd(OutFmcd), 'b*')
xlabel('Mahalanobis Distance')
ylabel('Robust Distance')
title('Distance Plot, Fast MCD method')

采纳的回答

Adam Danz
Adam Danz 2020-7-12
编辑:Adam Danz 2020-7-13
You just need to modify either of the two answers received for similar questions in the past (listed under your question).
To modify this answer, you just need to replace the centerPoint_x, centerPoint_y values with the coordinates you're using to define the quadrants.
Based on your image it would look something like,
centerPoint_x = 15; % approximate guess based on image
centerPoint_y = 18; % approximate guess based on image
  5 个评论
Adam Danz
Adam Danz 2020-7-13
编辑:Adam Danz 2020-7-15
You need to exchange "x" and "Y" with whatever values you're using to define the center point. Don't just copy-paste without doing the thinking.

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Price and Analyze Financial Instruments 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by