Calculating Harmonic Average in Matlab Function

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Mizo Amreya
Mizo Amreya 2020-7-12
评论： Mizo Amreya 2020-7-13
Hello,
I'm trying to calculate harmonic average in a Matlab function.
When I wrote the code below, I noticed Matlab doesn't seem to understand (i) as a counter variable.
Please advise why is this and how to resolve it. Thanking you in advance.
In main code I have:
kx = [10,20,30];
ky = [70,80,90];
In a function, I have:
function [harmonic_average] = harmonic_perm(kx,ky)
kxharmforward(i) = 2*(kx(i)*kx(i+1))/(kx(i)+kx(i+1)); % harmonic average for 20 & 30
kxharmbackward(i) = 2*(kx(i)*kx(i-1))/(kx(i)+kx(i-1)); % harmonic average for 10 & 20
kyharmupward(i) = 2*(ky(i)*ky(i+1))/(ky(i)+ky(i+1)); % harmonic average for 80 & 90
kyharmdownward(i) = 2*(ky(i)*ky(i-1))/(ky(i)+ky(i-1)); % harmonic average for 70 & 80
end
This is the error I get when I run the code
Array indices must be positive integers or logical values.
Error in harmonic_perm (line 3)
harmonic_average(i) = 2*(kx(i)*kx(i+1))/(kx(i)+kx(i+1));
Error in Main_Code (line 139)
harnomic_average(i)=harmonic_perm(kx(i),ky(i))

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回答（1 个）

David Hill
David Hill 2020-7-12
What is ky? Why not just perform vectorized? No need to index into k. k can be any length vector and the below will calculate the harmonic mean.
function harmonic_average = harmonic_perm(k)
harmonic_average = numel(k)/sum(1./k);
end
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David Hill
David Hill 2020-7-13
function harmonic_average = harmonic_perm(kx,ky)
harmonic_average=zeros(1,4);
for i=1:2
harmonic_average(i) = 2/sum(1./kx(i:i+1));
harmonic_average(i+2)= 2/sum(1./ky(i:i+1));
end
end

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