loop or other better solution for mixing?
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Hello, I am new to Matlab and want to do some mixing, and wonder if there is any better solution other than looping.
Basically, I want to mix any number of ingredients to make one solution. The percentage of the ingredients added up should equal to 100%. The percentage of each ingredient can be from 0% to 100%. I need to go through and save all the possible compositions with distinct names, and do calculations in order to find out the best composition.
Starting with two databases A and B, each with 4 columns of numerical data. I will need to produce and save all the mixed combination. For example, 10% of each column in A add 90% of the corresponding column in B, and save the result. The total percentage is 100%. This could be done with loop. x=0:0.1:1, C=x*A+(1-x)*b. This seems straightforward, if I only have two databases A and B.
If I have three databases, A, B and C, to produce D. So I need two loops?
If I have A, B, C and D, to produce E, so I need to have three loops?
If I want to mix more, do I have to create another loop again?
As the number of the databases I want to mix increase, this looping solution seems inefficient. Because everytime the numer of database changes, I need to rewrite my code again.
I was wondering if there is any better solution for this problem. So it does not need me to redo the coding even if I change the number of databases to be mixed. I hope I only need one code to run whatever number of databases that I want to mix.
Thank you very much.
2 个评论
Steven Lord
2020-7-13
Are the ingredients able to be continuously measured (i.e. 1.2345 mL of water) or are they discrete (1 egg, 2 eggs, but not 1.2345 eggs)?
Do you need the values of all possible combinations or do you need to find an optimal (according to some objective) combination?
Some of the functions in Optimization Toolbox or Global Optimization Toolbox may help particularly if your measurements are continuous.
addy fang
2020-7-13
回答(1 个)
Walter Roberson
2020-7-13
nd = 4; %number of databases, adjust as needed
vec = 0 : 0.1 : 1;
[P{1:nd}] = ndgrid(vec);
total = sum(cat(nd+1, P{:}), nd+1);
match = ismembertol(total, 1);
mixtable = cell2mat(cellfun(@(C) C(match), P, 'uniform', 0));
Each column of mixtable is now a percentage of the corresponding database to use.
10 个评论
Walter Roberson
2020-7-13
编辑:Walter Roberson
2020-7-13
nd = 4;
data = cell(nd, 1);
for K = 1 : nd
filename = sprintf('data%d.txt', K);
data{K} = readmatrix(filename);
end
vec = 0 : 0.1 : 1;
[P{1:nd}] = ndgrid(vec);
total = sum(cat(nd+1, P{:}), nd+1);
match = ismembertol(total, 1);
mixtable = cell2mat(cellfun(@(C) C(match), P, 'uniform', 0));
NM = size(mixtable,1);
for K = 1 : NM
mix = mixtable(K,:);
mixture = sum(cell2mat(arrayfun(@(C, frac) C{1}*frac, reshape(mix,1,1,[]), 'uniform', 0)), 3);
filename = "mix" + strjoin(compose("%.1f", mix), "_") + ".txt";
save(filename, 'mixture', '-ascii');
end
An example filename that it would produce would be mix0.8_0.9_0.1_1.0_0.6.txt
madhan ravi
2020-7-13
data = cell(nd, 1)
Walter Roberson
2020-7-13
Which line was the error on?
addy fang
2020-7-13
编辑:Walter Roberson
2020-7-13
Walter Roberson
2020-7-13
That code is wrong. You need to go back to the version I posted and work with that.
Walter Roberson
2020-7-13
Ah... I will need to reconstruct my thoughts about that line; it is certainly wrong...
addy fang
2020-7-14
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