how to assign value to a specific position in cell

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SM
SM 2020-7-13
评论： Walter Roberson 2020-7-17
A={[10,11,10,7],[7,8,7,6],[11,10,9,9],[7,5,11,5];[9,8,6,11],[10,6,9,7],[6,12,8,9],[7,10,12,9];[10,7,12,6],[8,11,7,5],[8,5,9,9],[10,10,10,10]};
B= [1,1,0,1;0,1,1,1;1,0,1,1;0,1,1,0];
[a,b]=find(~B);
for i=1:numel(a)
A{a(i),b(i)}=[100 100 100 100];
end
Is there any other ways instead of using for loop?

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采纳的回答

Walter Roberson
Walter Roberson 2020-7-13
if size(B,1) > size(A,1)
A(size(B,1),1) = {}; %extend A if needed
end
if size(B,2) > size(A,2)
A(1,size(B,2)) = {}; %extend A if needed
end
A(~B) = {[100 100 100 100]}; %replaces the find and the loop
  2 个评论
SM
SM 2020-7-13
编辑：SM 2020-7-13
Excellent solution. Thank you!
Is there any other ways instead of using for loop for this one?
A={[10,11,10,7],[7,8,7,6],[11,10,9,9],[7,5,11,5];[9,8,6,11],[10,6,9,7],[6,12,8,9],[7,10,12,9];[10,7,12,6],[8,11,7,5],[8,5,9,9],[10,10,10,10]};
C=[1 1 0 1;0 1 1 1;1 0 1 1; 0 1 1 0];
[a,b]=find(~C);
for i=1:numel(a)
for j=1:size(A,1)
A{j,a(i)}(b(i))=100;
end
end
Thanks in advance!
Walter Roberson
Walter Roberson 2020-7-17
You might be able to hide loops behind some cellfun() or arrayfun(), and abusing subsasgn() to do assignments using function call syntax...but otherwise, NO.

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