Removing replication in matlab

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Mohamed Jamal 2020-7-14

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https://ww2.mathworks.cn/matlabcentral/answers/564839-removing-replication-in-matlab

评论： Mohamed Jamal 2020-7-14

Hi guys, I have string like this

str= '000000011111100000000000000000000000000000000000111111100000000000000000000011110000000000000000000000000001111111001101'

I want to remove replication of zero and ones in that string this means , the output would be like this '010101010101' without replication of zero or ones ... *be careful that I dont know number of replication of zeros or ones in the str string ...

any help please how can I do that in matlab? thanks alot.

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Answer 1

madhan ravi 2020-7-14

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https://ww2.mathworks.cn/matlabcentral/answers/564839-removing-replication-in-matlab#answer_465548

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regexprep(str,{'0+','1+'},{'0','1'})

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Mohamed Jamal 2020-7-14

Appreciated!!!!!!

could you please and I appreciate your effort much ! to help me here : https://www.mathworks.com/matlabcentral/answers/564524-problem-in-matlab-implementation-zero-crossings-detector?s_tid=prof_contriblnk

thanks alot

John D'Errico 2020-7-14

Better than my solution of course.

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Answer 2

John D'Errico 2020-7-14

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But the string, after you remove the replicates will always be identically the same, just alternating 0's and 1's. If the first element is a '0', then the string will be '010101010...'. If the first element is a 1, then it will be opposite. The only question is the length of the string.

My point is, don't even worry about removing the replicated elements. Just create the final result as it must be.

newstr = str(1);
if newstr == '0'
  % Count the number of '10' transitions
  newstr = [newstr,repmat('10',[1,numel(strfind(str,'10'))])];
  
  % was the final element a '1'
  if str(end) == '1'
    newstr = [newstr,'1'];
  end
else
  % then the first element was a '1'
  % So count the number of '01' transitions
  newstr = [newstr,repmat('01',[1,numel(strfind(str,'01'))])];
  
  % was the final element a '0'
  if str(end) == '0'
    newstr = [newstr,'0'];
  end
end