Function for angle to output 1 or 0
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I'm trying to write a funciton that has two outputs, 1 or 0. Based on the angle if its between 0 and 34 degrees its = 0. Then if it's between 34 and 68 = 1. That repeats itself 360 degrees. If anyone can help with the code for the fucntion it would be great! Currently I had:
function Thet = Theta (A)
returnValue = 1;
if mod(A, 68)~= 0
returnValue = 0;
end
Thet = returnValue;
end
采纳的回答
madhan ravi
2020-7-14
Theta = @(x) 0*(x>=0 & x<34) + 1*(x>=34 & x<=68)
3 个评论
Image Analyst
2020-7-14
I don't see the pattern repeating all the way out to 360:
Theta = @(x) 0*(x>=0 & x<34) + 1*(x>=34 & x<=68)
angle = 0 : 360
out = Theta(angle)
madhan ravi
2020-7-14
编辑：madhan ravi
2020-7-14
Ok should have included that as well:
x = 394; % for example
Wanted = Theta(x)
function Thet = Theta(x)
x = mod(x, 360);
Thet = 0*(x>=0 & x<34) + 1*(x>=34 & x<=68);
end
Kyle Grimaldi
2020-7-14
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