Dynamic Matrices in Matlab
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Hi!
Yesterday, I had a very similar question, now I want something a bit more advanced. So I have coded already:
data = [234,3,8;457,5,7;611,7,3;234,9,12]
ID = data(:,1);
X = data(:,2);
U = unique(ID)
data(U(i) == data(:,1),3)
display data
Now I want to create a matrix, where the first column would be the first column of the data matrix above (i.e. "id"). And all the following collumns would then store the values in the third column of data belonging to this id. So it would look like:
[234, 8,12; 457, 7,0; --- ]
But, obviously, I could not set the dimensions of this matrix from the beginning on, the number of columns would have to be dynamical. Is that possible?
Thanks
回答(2 个)
Andrei Bobrov
2012-12-13
编辑:Andrei Bobrov
2012-12-13
[a,b,c] = unique(data(:,1));
d = accumarray(c,data(:,3),[],@(x){sort(x)});
n = cellfun(@numel,d);
m = numel(a);
out = [a, zeros(m,max(n))];
for j1 = 1:m
out(j1,2:n(j1)+1) = d{j1};
end
Walter Roberson
2012-12-13
Is the number of matching elements possibly different between the id's? If it is, then you cannot do this with a numeric matrix and need to use a cell array instead.
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