How to collapse within a column vector

Hello,
I am trying to collapse a long column to a shorter one by suming across elements. For instance, if I have:
x =
1
2
3
4
5
6
7
8
9
I would like to sum up every three elements and arrive at:
y= 6
15
24
This is basically the 'collapse' function in Stata but I'm struggling to do it in Matlab. Thanks for your advide.

 采纳的回答

You can use the sum function after reshape your vector into a matrix
vX = 1:9;
Interval = 3;
mX = reshape(vX, Interval, numel(vX)/Interval)
mX =
1 4 7
2 5 8
3 6 9
sum(mX)
ans =
6 15 24
/!\ reshape() won't work if the number of elements in vX is not a multiple of Interval

4 个评论

Thank you very much -- it works well!
A related question is.. how would you do it if you had a matrix rather than a column vector? For instance, if I have a 6 by 3 matrix X
X =
1 4 7
2 5 8
3 6 9
1 4 7
2 5 8
3 6 9
How could I turn this into 3 by 3 by suming up every two elements in each column and get:
Y=
3 9 15
4 10 16
5 11 17
I tried to use reshape again and it seems the matrix is sliced in an inconvinient way.. Thank you very much for your time!
How about:
X = [1 4 7; 2 5 8; 3 6 9; 1 4 7; 2 5 8; 3 6 9];
X = X(:);
X = reshape(X,2,length(X)/2);
Y = sum(X);
Y = reshape(Y, 3, length(Y)/3);
Works perfectly - thank you very much!

请先登录,再进行评论。

更多回答(1 个)

One possibility is:
x = 1:12;
for i = 1:length(x)/3
p = 3*(i-1)+1;
y(i) = sum(x(p:p+2));
end

类别

帮助中心File Exchange 中查找有关 Performance and Memory 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by