Data dimensions must agree

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Asif Rashid
Asif Rashid 2020-7-18
评论： Asif Rashid 2020-7-20
i have a function z which has two variables x and y. z , x and y are vectors of length 20. While plotting a function, MATLAB says that 'Data dimensions must agree'. Using the commands
x=PitchAngle;
y=TipSpeedRatio;
[xx,yy]=meshgrid(x,y);
zz=PowerCoefficient;
z=reshape(zz,[5,4])
mesh(x,y,z)
I dont know whether i am using the right command. Please lead me to the right way. Thankyou
  1 个评论
Asif Rashid
Asif Rashid 2020-7-18
z=reshape(zz,[5,4])
converts vector into a matrix as MATLAB needs z to be a matrix not a vector

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采纳的回答

madhan ravi
madhan ravi 2020-7-18
编辑：madhan ravi 2020-7-18
x = reshape(x, 1, []);
y = reshape(y, 1, []);
[xx, yy]=meshgrid(x,y);
z = repmat(zz(:), 1, size(xx, 2));
mesh(xx, yy, z)
  4 个评论
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Asif Rashid
Asif Rashid 2020-7-18
Thankyou Sir. It worked
Asif Rashid
Asif Rashid 2020-7-20
Sir i i want to change the axis so when i wrote this code
x=reshape(TipSpeedRatio,1,[]);
y=reshape(PitchAngle,1,[]);
[xx,yy]=meshgrid(x,y);
z = repmat(PowerCoefficient(:), 1, size(xx, 2));
mesh(xx,yy,z)
I cant plot the figure successfully. untill command
z = repmat(PowerCoefficient(:), 1, size(xx, 2));
the code is running successfully but when i write
mesh(xx,yy,z)
i see the error that
Z must be a matrix, not a scalar or vector.
how may i fix this error. please guide

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