Data dimensions must agree

i have a function z which has two variables x and y. z , x and y are vectors of length 20. While plotting a function, MATLAB says that 'Data dimensions must agree'. Using the commands
x=PitchAngle;
y=TipSpeedRatio;
[xx,yy]=meshgrid(x,y);
zz=PowerCoefficient;
z=reshape(zz,[5,4])
mesh(x,y,z)
I dont know whether i am using the right command. Please lead me to the right way. Thankyou

1 个评论

z=reshape(zz,[5,4])
converts vector into a matrix as MATLAB needs z to be a matrix not a vector

请先登录,再进行评论。

 采纳的回答

madhan ravi
madhan ravi 2020-7-18
编辑:madhan ravi 2020-7-18
x = reshape(x, 1, []);
y = reshape(y, 1, []);
[xx, yy]=meshgrid(x,y);
z = repmat(zz(:), 1, size(xx, 2));
mesh(xx, yy, z)

4 个评论

Sir, Thankyou for your Answer. I have tried implementing this but until command 4 , the code is running without errors but when i write 5th command that is mesh(x,y,z) amd run the program, i am encountered with the same error 'Data dimensions must agree'
command 1
x=reshape(PitchAngle,1,[]);
command 2
y=reshape(TipSpeedRatio,1,[]);
command 3
[xx,yy]=meshgrid(x,y);
command 4
z = repmat(PowerCoefficient(:), 1, size(xx, 2));
command 5
mesh(x,y,z)
on the workspace
x is shown ( value) as 1x20 double
xx is shown (value) as 1x20 double
y is shown (value) as 44250
yy is shown (value) as 1x20 double
z is shown (value) as 20x20 double
Please guide
Thankyou Sir. It worked
Sir i i want to change the axis so when i wrote this code
x=reshape(TipSpeedRatio,1,[]);
y=reshape(PitchAngle,1,[]);
[xx,yy]=meshgrid(x,y);
z = repmat(PowerCoefficient(:), 1, size(xx, 2));
mesh(xx,yy,z)
I cant plot the figure successfully. untill command
z = repmat(PowerCoefficient(:), 1, size(xx, 2));
the code is running successfully but when i write
mesh(xx,yy,z)
i see the error that
Z must be a matrix, not a scalar or vector.
how may i fix this error. please guide

请先登录,再进行评论。

更多回答(0 个)

类别

帮助中心File Exchange 中查找有关 Operating on Diagonal Matrices 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by