Problem with using `reshape` to reorder the matrix.

1 次查看(过去 30 天)
I am trying to reorder my matrix "by block" in columns.
See the code below, it is a mini case of my problem. It only has 2 "blocks"(In the graph above, it has 3).
a = [1,7,4,10;
2,8,5,11;
3,9,6,12];
output = [a(:,[1,2]);a(:,[3,4])];
I think this way is not very delicate. I think I should use the combination of transpose and reshape. If it is impossible, I would like to know either.

回答(2 个)

julian navas
julian navas 2020-7-19
编辑:julian navas 2020-7-19
I think I don't get 100% your question but from the shape of 'output' see if this is what you need
a(:,[2,3])=a(:,[3,2])
reshape(a,[],2)
ans =
1 7
2 8
3 9
4 10
5 11
6 12

Image Analyst
Image Analyst 2020-7-19
编辑:Image Analyst 2020-7-19
Did you just try a dumb for loop?
m = reshape(1:63, 3, 21)
[rowsm, columnsm] = size(m)
outputColumns = 7 % Columns to "lock"
numGroups = columnsm / outputColumns;
outputRows = rowsm * numGroups
m2 = zeros(outputRows, outputColumns);
row = 1;
for col = 1 : numGroups
col1 = (col-1) * outputColumns + 1;
col2 = col1 + outputColumns - 1;
m2(row:row+rowsm-1,:) = m(:, col1:col2);
row = row + rowsm;
end
m2
In my example I started with a 3x21 matrix and used 7 columns for a groups, so the output has 7 columns and (21/7) * 3 = 9 rows.
m =
1 4 7 10 13 16 19 22 25 28 31 34 37 40 43 46 49 52 55 58 61
2 5 8 11 14 17 20 23 26 29 32 35 38 41 44 47 50 53 56 59 62
3 6 9 12 15 18 21 24 27 30 33 36 39 42 45 48 51 54 57 60 63
m2 =
1 4 7 10 13 16 19
2 5 8 11 14 17 20
3 6 9 12 15 18 21
22 25 28 31 34 37 40
23 26 29 32 35 38 41
24 27 30 33 36 39 42
43 46 49 52 55 58 61
44 47 50 53 56 59 62
45 48 51 54 57 60 63

类别

Help CenterFile Exchange 中查找有关 Resizing and Reshaping Matrices 的更多信息

产品


版本

R2019a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by