Well-identified fitted process model does not behave like data on simulink

Question

julian navas 2020-7-19

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/567273-well-identified-fitted-process-model-does-not-behave-like-data-on-simulink

评论： julian navas 2020-7-21

Hello, and thanks for taking your time to read my question.

I have a set of experiments that I am trying to identify using the system identification tool, and I succesfully obtained a process model (2nd order transfer function, 2 inputs 1 output + delay each) and a state-space model (order 2). The fits in the identification tool (model output window) are almost perfect but when I try to simulate the same data with the process model (idmodel) block in simulink the output is completely messed up. I used the exact same simulink model with the state-space fitted model and the output is congruent with the toolbox model output window. I think the reason is because I can't set initial values for transfer function identified models like I can do for state-space models .

Is there a way to set initial values for transfer function models on simulink? I already tried converting the process model to a state space model with ss() and use a state space block but it didn't work, I assume because in the model options I selected a first order disturbance term. Also I tried fitting the model with zero initial conditions but the results were the same (bad). I posted this question here as well.

My objective is to simulate the identified process model just as it appears in the system identification tool (model output) window, maybe the current approach is not the correct one so it would be absolute beneficial to me if anyone knows how to do so and is kind enough to set me on the right path.

Figure 1. Model output window. Yellow is SS model, blue is process model

Figure 2. Process model parameter window. Fit options are as displayed, everything else is on default values.

Figure 3. Simulation of process model with simulink. It can be observed the fit (blue) does not correspond to data (yellow)

Figure 4. Simulation of state space model with simulink.It is coherent with the model output window of figure 1

Figure 5. Simulink idmodel block parameters. Left: state space model, it allows to enter initial conditions. Right: process model. Can't set initial conditions.

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

julian navas 2020-7-20

Update

I can compare the models and the data using [y,fit, x0]=compare(sys, data) but still can't figure out how to do this in simulink. Please any help is greatly welcome.

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Rajiv Singh 2020-7-21

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/567273-well-identified-fitted-process-model-does-not-behave-like-data-on-simulink#answer_468786

You are almost there. Convert the model into state-space form and use it for simulation. For initial conditions, you will need to run FINDSTATES command on the dataset whose output you are trying to match. See:

https://www.mathworks.com/help/ident/ug/estimate-initial-conditions.html

7 个评论
显示 5更早的评论隐藏 5更早的评论

julian navas 2020-7-21

在 MATLAB Online 中打开

I tried your answer and got mixed results. Let me explain: I run this to convert my idproc model to ss and to estimate initial states.

model=idss(T3s_2d);
findstates(model,run_data_s{8})
ans =
         0
         0
  186.2812
  -34.2960
  106.0995
  
findstates(T3s_2d,run_data_s{8})
ans =
         0
         0
  186.2812
  -34.2960
  106.0995
  

Although the SS matrices are not in the canonical form of the other models, it doesn't matter, the initial conditions are the same. I use compare to see what their output is like on the model output window of the system identification toolbox

compare(run_data_s{8}, T3s_2d, model)

Excellent. Both appear with the same name because that's the internal name in the model properties even after conversion. Now I try it in simulink but it doesn't work as expected.

I thought that maybe I was missing noise information, then checked the 'Add noise' button in the idmodel parameters but it got much much more worse.

This is better than what I initially had, so it's progress, but still not quite there yet. Do you have more ideas on how to handle this strange (for me) behaviour?

julian navas 2020-7-21

在 MATLAB Online 中打开

Of course, here it is

>> model=idss(T3s_2d)
model =
  Continuous-time identified state-space model:
      dx/dt = A x(t) + B u(t) + K e(t)
       y(t) = C x(t) + D u(t) + e(t)
 
  A = 
               x1          x2          x3          x4          x5
   x1   -0.001739  -0.0003834           0           0           0
   x2   0.0002441           0           0           0           0
   x3           0           0    -0.02643  -0.0006169           0
   x4           0           0   0.0009766           0           0
   x5           0           0           0           0   -0.002102
 
  B = 
        T_{pv}   P_{pv}
   x1  0.01563        0
   x2        0        0
   x3        0     0.25
   x4        0        0
   x5        0        0
 
  C = 
             x1       x2       x3       x4       x5
   LOD        0  0.01396        0   0.1303   0.1476
 
  D = 
        T_{pv}  P_{pv}
   LOD       0       0
 
  K = 
        LOD
   x1     0
   x2     0
   x3     0
   x4     0
   x5  0.25
 
  Input delays (seconds): 630  8.79 
 
Name: T3s_2d
Parameterization:
   FREE form (all coefficients in A, B, C free).
   Feedthrough: none
   Disturbance component: estimate
   Number of free coefficients: 45
   Use "idssdata", "getpvec", "getcov" for parameters and their uncertainties.
Status:                                 
Created by conversion from idproc model.
>> T3s_2d
T3s_2d =
Process model with 2 inputs: y = G11(s)u1 + G12(s)u2         
  From input "T_{pv}" to output "LOD":                       
                  Kp                                         
  G11(s) = ----------------- * exp(-Td*s)                    
           (1+Tp1*s)(1+Tp2*s)                                
                                                             
         Kp = 0.56884                                        
        Tp1 = 17989                                          
        Tp2 = 593.88                                         
         Td = 629.61                                         
                                                             
  From input "P_{pv}" to output "LOD":                       
                  Kp                                         
  G12(s) = ----------------- * exp(-Td*s)                    
           (1+Tp1*s)(1+Tp2*s)                                
                                                             
         Kp = 52.797                                         
        Tp1 = 37.875                                         
        Tp2 = 43828                                          
         Td = 8.79                                           
                                                             
  An additive ARMA disturbance model exists for output "LOD":
      y = G u + (C/D)e                                       
                                                             
      C(s) = s + 0.03899                                     
      D(s) = s + 0.002102                                    
                                                             
Name: T3s_2d
Parameterization:
    'P2D'    'P2D'
   Number of free coefficients: 10
   Use "getpvec", "getcov" for parameters and their uncertainties.
Status:                                                        
Estimated using PROCEST on time domain data "T3s_edit".        
Fit to estimation data: [91.07 94.18 92.84]% (prediction focus)
FPE: 0.1222, MSE: [0.1101 0.04204 0.07042]  

Is there a way to convert idproc to idss in canonical observable form?

Rajiv Singh 2020-7-21

在 MATLAB Online 中打开

OK, thanks. Call FINDSTATES with Inf horizon, as in

x0 = findstates(sys, data, Inf)

since you are after simulation worthiness.

julian navas 2020-7-21

That fixes it. Thank you very much again for your valuable help.

请先登录，再进行评论。

Well-identified fitted process model does not behave like data on simulink

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

采纳的回答

7 个评论
显示 5更早的评论隐藏 5更早的评论

更多回答（0 个）

另请参阅

类别

标签

产品

版本

Community Treasure Hunt

Well-identified fitted process model does not behave like data on simulink

1 个评论 显示 -1更早的评论隐藏 -1更早的评论

采纳的回答

7 个评论 显示 5更早的评论隐藏 5更早的评论

更多回答（0 个）

另请参阅

类别

标签

产品

版本

Community Treasure Hunt

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

7 个评论
显示 5更早的评论隐藏 5更早的评论