# implementation of a matrix

2 次查看（过去 30 天）
Franziska Bömann 2020-7-19
Hello! I want to implement the following matrix:
where is a given vector of random indices
Can someone help me to implement that?
##### 3 个评论显示 1更早的评论隐藏 1更早的评论
Franziska Bömann 2020-7-19
yes, I did, but I cannot understand how to implement matrices, thats why I'm always asking about matrices.
Ok , can you upload what you have tried?

### 采纳的回答

This should do:
rng(42)
n = 3;
x = rand(n,1);
A = ones(n,n+1);
Differences = x-x';
for idx=2:n+1
A(:,idx) = A(:,idx-1).*Differences(:,idx-1);
end
x
A
x =
0.3745
0.9507
0.7320
A =
1.0000 0 0 0
1.0000 0.5762 0 0
1.0000 0.3575 -0.0782 0
##### 1 个评论显示 -1更早的评论隐藏 -1更早的评论
It’s a homework :/

### 更多回答（1 个）

Bruno Luong 2020-7-19

n = 3;
x = rand(n+1,1);
A = cumprod([ones(size(x)), (x-x(1:end-1).')], 2)
##### 1 个评论显示 -1更早的评论隐藏 -1更早的评论

But why though? It’s pretty obvious it’s a homework question? It’s not a homework solving contest XD.

### 类别

Help CenterFile Exchange 中查找有关 Calendar 的更多信息

### Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by