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Index in position 2 exceeds array bounds (must not exceed 2).

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Anjolaoluwa Bamtefa
评论： madhan ravi 2020-7-20
I am trying to write code to delete every column of a matrix that has 0 in the second row so I am only left with the columns that have values in that second row. The code works okay and does that but I keep getting the error "Index in position 2 exceeds array bounds (must not exceed 2)."
I need to use the values after and I keep running into the same problem. Can I get some help?
This is what my code looks like :
c= length(fill);
while c >= 1
if fill(2,c) == 0;
fill(:,c) = [];
c = length(fill);
else
c = c - 1;
end
end
fill is typically a 3 by 30 ish matrix (it changes for each set of data).

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采纳的回答

madhan ravi
madhan ravi 2020-7-20
Never name a variable fill !
ix = FiLL(2, :) == 0;
FiLL(:, ix) = []

更多回答（1 个）

Bhupendra Prajapati
length function will give maximum of rows or columns in the matrix, you should use size function to calculate number of columns
You can use the code given below to do your task.
[r,c]=size(fill)
id=1;
while(id<=c)
if(any(fill(2,id)==0))
fill(:,id)=[];
c=c-1;
else
id=id+1;
end
end
  1 个评论
madhan ravi
madhan ravi 2020-7-20
As mentioned above , not a good idea to use fill as a variable name. And loop is totally unnecessary here.

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