Line 34 * unknown operator
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Confused about why this doesnt work at the end. The arrays all have the correct dimensions. Any help would be appreciated.
A=3;
E=4;
I=5;
le=2;
thetae=[pi/2;pi/4;pi/6];
c=cos(thetae);
s=sin(thetae);
N=numel(thetae); %counts elements of thetae vector
T=cell(1,N);
keprime=cell(1,N); %makes empty celled matrix
for i=1:N
keprime{i}=[A*E/le,0,0,-A*E/le,0,0;
0,12*E*I/le^3,6*E*I/le^2,0,-12*E*I/le^3,6*E*I/le^2;
0,6*E*I/le^2,4*E*I/le,0,-6*E*I/le^2,2*E*I/le;
-A*E/le,0,0,A*E/le,0,0;
0,-12*E*I/le^3,-6*E*I/le^2,0,12*E*I/le^3,-6*E*I/le^2;
0,6*E*I/le^2,2*E*I/le,0,-6*E*I/le^2,4*E*I/le];
end
for i=1:N
T{i}=[c(i),s(i),0,0,0,0; %Transfer Matrix set translates global coordinates to local coordinates
-s(i),c(i),0,0,0,0;
0,0,1,0,0,0;
0,0,0,c(i),s(i),0;
0,0,0,-s(i),c(i),0;
0,0,0,0,0,1];
end
T1=T(1);
T2=T(2);
T3=T(3);
ke1=T1.'*keprime(1)*T1;
ke2=T2.'*keprime(2)*T2;
ke3=T3.'*keprime(3)*T3;
2 个评论
madhan ravi
2020-7-20
Revived your question from the spam quarantine.
JONATHAN DAVID JR FREEMAN
2020-7-20
采纳的回答
madhan ravi
2020-7-20
1 个投票
After the second loop use {} instead of () by the way those two loops can be reduced to one single loop.
2 个评论
JONATHAN DAVID JR FREEMAN
2020-7-20
madhan ravi
2020-7-20
I don’t know why there is an exhaustive first loop , you don’t seem to change anything in each iteration. Simply repmat() tk replicate the elements.
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