Help me generating this series of number.

2 次查看(过去 30 天)
White flag.
I'm trying to make a series of number like below:
1
2
5
10
20
50
100
200
500
...
...
...
1000000000
2000000000
5000000000
but i need a for-end command first
for i=1:20
because i want to use that "20" in other procedure. And the generated numbers willl also be input in another procedure which requires them to be real positive integer.
could you help me?

采纳的回答

Andrei Bobrov
Andrei Bobrov 2011-4-17
without loop for
reshape(cumprod([1 2 5;10*ones(9,3)])',[],1);
with loop for
P = zeros(30,1);
for ii = 1:20
if rem(ii,2) == 0,
P(3*(ii/2)-2+(0:2)) = [1;2;5]*10^(ii/2-1);
end
end
  3 个评论
Albaihaqi Albaihaqi
May I ask?
why do you use
P(3*(ii/2)-2+(0:2))= ...
instead of
P(ii)= ...
?
Andrei Bobrov
Andrei Bobrov 2011-4-18
Because, it is necessary to fulfill your two conditions: length (P) = 30, i = 1:20

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更多回答(1 个)

Albaihaqi Albaihaqi
Thanks dude for a lot of help... I really need this...
Could I ask you for another problem I might have in the future? Thanks

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