How can i use the 'mod' function in an Embedded Matlab function?

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Zoltan 2012-12-17

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I have the following function. I want to use this algorithm in an embedded Matlab function in simulink.

function y   = fcn( u )
y=[0;0;0;0;0;0;0;0;0;0];
newu=0;
nr=0;
s=false;
if u<0 s=true;
end
while u~=0 
  newu=newu*10+mod(u,10);
  u=(u/10);
  nr=nr+1;
end;
for i=nr:0   
  y(i)=mod(newu,10);
  newu=(newu/10);
end;
for i=0:nr 
y = y+65;
end
end

After compilation it gives me the error :'Function 'mod' is not defined for values of class 'embedded.fi'. 'u'(input value) being of class 'embedded.fi'. What do i have to change to get my output value?

Thank you, Zoli

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Walter Roberson 2012-12-19

Double-check the parity of the line. But even more so, double check how the heck an 8 bit result is generating a negative number below -128, as 8 bit signed values can only be in the range -128 to +127 . Check your scope settings.

Zoltan 2012-12-20

thanks

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回答（1 个）

Azzi Abdelmalek 2012-12-17

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/56817-how-can-i-use-the-mod-function-in-an-embedded-matlab-function#answer_68763

编辑：Azzi Abdelmalek 2012-12-17

在 MATLAB Online 中打开

In the below part of your code

while u~=0 
  newu=newu*10+mod(u,10);
  u=(u/10);
  nr=nr+1;
end;

newu increases rapidly to infinity. that's what causes a problem when

y(i)=mod(newu,10);

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Azzi Abdelmalek 2012-12-17

编辑：Azzi Abdelmalek 2012-12-17

Yes, but after 309 iterations, 10^309=inf

In the above example, nr=324

Walter Roberson 2012-12-17

This is only a problem if the fi object has a representation for infinity and if the input is infinity. Otherwise abs(u) is diminishing in each step and there would be a finite end to the process. It could potentially overflow the buffer of 10 y locations, but that would depend upon the maximum value possible for that particular fi object.

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