How to find out zeros and their indices in a matrix?

1 次查看（过去 30 天）
SM
SM 2020-7-21
评论： SM 2020-7-21
I have an input matrix of size 3*13 double:
input=[0 0 1 0 0 0 1 1 1 0 0 0 0;
0 1 0 0 1 1 0 0 0 1 0 1 0;
0 1 1 1 1 0 0 0 1 0 0 1 0];
I want to know how many zeros subsequently have in
input(2,:)
The output should be:
output=[1 2 3 1 1];
I also want to know their starting index of zeros. It should look like:
index=[1 3 7 11 13];
How can i solve this problem?

请先登录，再回答此问题。

采纳的回答

Bruno Luong
Bruno Luong 2020-7-21
编辑：Bruno Luong 2020-7-21
v=input(2,:)>0; % remove >0 if your matrix contains only 0 or 1
d = diff([1, v, 1]);
index = find(d==-1)
output = find(d==1)-index

更多回答（1 个）

Matt J
Matt J 2020-7-21
编辑：Matt J 2020-7-21
One way is to use this FEX submission,
https://www.mathworks.com/matlabcentral/fileexchange/78008-group1s
H=group1s(~input(2,:));
output=histcounts(H); output(1)=[];
[~,index]=unique(H); index(1)=[];

类别

在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by