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Hi,
I have a struct 1*100 with 33 Fields. I would like to write this struct several times and then access the respective struct (which always has the same name) with an index. Index 1 = struct 1 / index 2 = struct 2. Is this working? I dont want to use different names for each struct. Thanks.

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Arthur Roué
Arthur Roué 2020-7-21

0 个投票

Yes, you can totally creat a structure array.
s(1) = struct('f1','a','f2', 1)
% Add a value to field f2 in element 3
s(3).f2 = 3;
% s(2) is empty
s(2).f1

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Peter Meier
Peter Meier 2020-7-21
I understand. The name of this struct is s. But i want for example 899 1*3 structs with 2 fields with the name s. Not a 1*899 struct with 2 fields. Thx for your help. I hope you understand
Walter Roberson
Walter Roberson 2020-7-21
use an 899 x 3 struct if the field names are always the same. Or a 3 x 899 would be slightly more efficient if you are accessing in groups of 3
Peter Meier
Peter Meier 2020-7-21
The field names and the size are always the same only the data is different. I want to call the struct always with the same name but with another index. its like 1000 3x3 Matrix with the same name. like structA{1} / structA{2}
Walter Roberson
Walter Roberson 2020-7-21
S(3,75).A . /S(1,75).A
for example

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