how will use nested loop

2 次查看(过去 30 天)
hello my problem is that i have 11 value for any variable suppose i=1:11 and have another variable suppose b=2:12 also has 11 values now my question is that i want to find out value for i=1 for z=i*b total 11 values and for i=2 another 11 value of z and so on how i can use nested loop
  3 个评论
manoj saini
manoj saini 2012-12-19
for i=1 I want 11 values of i*b in one row for i=2 I want 11 values of i*b in one row for i=3 I want 11 values of i*b in one row AND SO ON..............
Walter Roberson
Walter Roberson 2012-12-19
Yes, and all of the Answers so far give you that.

请先登录,再进行评论。

采纳的回答

Muruganandham Subramanian
编辑:Muruganandham Subramanian 2012-12-19
try this:
z = zeros(11,11);
for a=1:11
for b=2:12
z(a,b)=a*b;
end
end
z(:,1)=[];
  2 个评论
Walter Roberson
Walter Roberson 2012-12-19
You declare z as 11 x 11, but then you use it as 11 x 12.
Because of the way MATLAB handles assignments to non-existant locations, this will work, but it does indicate a logic fault on your part.
Muruganandham Subramanian
编辑:Muruganandham Subramanian 2012-12-19
@walter..I agre your point..

请先登录,再进行评论。

更多回答(3 个)

Babak
Babak 2012-12-18
Z = zeors(11,11);
for i=1:11
for b=2:12
z=i*b;
end
end
  4 个评论
manoj saini
manoj saini 2012-12-19
sir now if my varible i=0.1:.11 and b also in point then how it will save
Image Analyst
Image Analyst 2012-12-19
If the number you're multiplying by is a fractional number, like 0.1 or 0.11 then you'll have to separate your index from your number, like I think you originally had in your message where you had a and b instead of i and b. You could just make the loop index from 1 to 11 and then create the array index from it like arrayIndex = i / 10 and then use arrayIndex in z() or wherever.

请先登录,再进行评论。


Walter Roberson
Walter Roberson 2012-12-18
z = bsxfun(@times, i(:), b);

Sean de Wolski
Sean de Wolski 2012-12-18
Code golf:
z=i'*b

类别

Help CenterFile Exchange 中查找有关 Loops and Conditional Statements 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by