Problem with using 'DisplayName' property in fplot()

2020 7 23
1 个回答
更新时间：2020 7 23
2 次查看（30 天）

0 个投票

Hello everbody,
I wrote a function to plot a limit value in a existing figure. You can see it below. This function works well without using 'DisplayName' in fplot().
If I want to use 'DisplayName' I have got the following error:
Error using plot
Error in color/linetype argument.
Error in fplot (line 154)
plot(xx,y,marker,'parent',cax)
Error in limits (line 48)
fplot(f, axes.XLim, 'DisplayName', 'Test')
Can someone help me to fix this problem.
Thank you in advance,
Lennart
function limits(fig, standard)
%% Code
axes = fig.CurrentAxes;
axes.NextPlot = 'add';
if strcmp(standard, 'ECE R10 10m QuasiPeak')
f1 = @(x) 32;
f2 = @(x) 32 + 15.13 .* log10(x/75000000);
f3 = @(x) 43;
elseif strcmp(standard, 'ECE R10 10m Average')
f1 = @(x) 22;
f2 = @(x) 22 + 15.13 .* log10(x/75000000);
f3 = @(x) 33;
elseif strcmp(standard, 'ECE R10 3m QuasiPeak')
f1 = @(x) 42;
f2 = @(x) 42 + 15.13 .* log10(x/75000000) ;
f3 = @(x) 53;
elseif strcmp(standard, 'ECE R10 3m Average')
f1 = @(x) 32;
f2 = @(x) 32 + 15.13 .* log10(x/75000000) ;
f3 = @(x) 43;
elseif strcmp(standard, 'ECE R10 EUB QuasiPeak')
f1 = @(x) 62 - 25.13 .* log10(x/3000000);
f2 = @(x) 52 + 15.13 .* log10(x/75000000) ;
f3 = @(x) 63;
elseif strcmp(standard, 'ECE R10 EUB Average')
f1 = @(x) 52 - 25.13 .* log10(x/3000000);
f2 = @(x) 42 + 15.13 .* log10(x/75000000) ;
f3 = @(x) 53;
else
error('Dies ist kein vorhandener Grenzwert!')
end
f = @(x) f1(x).*((30000000 <= x) & (x <= 75000000)) + f2(x).*((75000000 < x) & (x < 400000000)) + f3(x).*((400000000 <= x) & (x < 1000000000));
fplot(f, axes.XLim, 'DisplayName', 'Test')
end

2 个评论
显示 无 隐藏 无

Robert U
Robert U 2020-7-23
Problem seems not to be "DisplayName" property but the limits given by axes.XLim.
Kind regards,
Robert
Lennart Reich
Lennart Reich 2020-7-23
But without axes.XLim I have got the same error.

请先登录，再进行评论。

请先登录，再回答此问题。

回答（1 个）

madhan ravi
madhan ravi 2020-7-23
编辑：madhan ravi 2020-7-23

0 个投票

F = fplot(f);
set(F, 'DisplayName', 'Test')

8 个评论
显示 6更早的评论 隐藏 6更早的评论

Walter Roberson
Walter Roberson 2020-7-23
Right. DisplayName is not an option that is accepted by fplot(). fplot() only accepts some color related and marker related and line style related options, together with some mesh options.
Lennart Reich
Lennart Reich 2020-7-23
If I'm using it like you I have got the error:
Index exceeds matrix dimensions.
Error in fplot (line 56)
lims = args{2};
Error in limits (line 47)
F = fplot(f);
If I'm using it with axes.XLim():
F = fplot(f, axes.XLim);
set(F, 'DisplayName', 'Test');
I have got the error:
Error using matlab.graphics.Graphics/set
There is no DisplayName property on the Root class.
Error in limits (line 48)
set(F, 'DisplayName', 'Test');
madhan ravi
madhan ravi 2020-7-23
which fplot -all % ?
Hope you didn’t mess the stock file.
Lennart Reich
Lennart Reich 2020-7-23
@madhan ravi: I have got this as response:
C:\Program Files\MATLAB\R2015b\toolbox\matlab\specgraph\fplot.m
So I think this is right or?
@walter roberson: But why I can find it FunctionLine Properties. Besides they use 'LineWidth' in an example of the fplot function. This will give the same error.
Walter Roberson
Walter Roberson 2020-7-23
Ah, notice they are using R2015b.
Walter Roberson
Walter Roberson 2020-7-23
In R2015b,
[X,Y] = fplot(FUN,LIMS,...) returns X and Y such that Y = FUN(X). No plot is drawn on the screen.
So you have to do something like
curchild = get(axes,'Children');
fplot(f, axes.XLim);
newchild = get(axes, 'Children');
newline = setdiff(newchild, curchild);
set(newline, 'DisplayName', 'Test')
and at some point
legend show
Lennart Reich
Lennart Reich 2020-7-23
Yeah this works fine. Thank you Walter.

请先登录，再进行评论。

类别

在 帮助中心 和 File Exchange 中查找有关 Line Plots 的更多信息

产品

版本

R2015b

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by