How to insert NaNs on an array based on a condition some other array

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Shambhavi Adhikari
Shambhavi Adhikari 2020-7-24
回答： Matt J 2020-7-27
I have an array
A= [210,210,210,220,220,220,240]
B= [210,nan,nan,220,nan,nan,240]
C=[1,2,4,5,7,8,10]
and now i remove NaNs from B
index= find(~isnan(B))
and apply this index to B and C
New
B= [210,220,240]
and new
C=[1,5,10]
and now my condition is if
diff(B)<=10 & diff(C)<=4
, i insert NaNs between these indexes in A
so my final A is:
A= [210,210,210,220,nan,nan,240]
Can you please me do this?
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Jalaj Gambhir
Jalaj Gambhir 2020-7-27
Yeah, but how are you getting indices 5 & 6 to insert nan in array A, based on this condition? "diff(B)<=10 & diff(C)<=4" Please frame your question in a better way.

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回答（1 个）

Matt J
Matt J 2020-7-27
Using group1s from the File Exchange
https://www.mathworks.com/matlabcentral/fileexchange/78008-group1s
index = ~isnan(B);
nangroups = group1s(~index);
diffg = find(diff(B(index))<=10 & diff(C(index))<=4);
mask=any( nangroups==diffg(:) , 1)
A(mask)=nan

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