Running code and getting error about vector must be the same length
显示 更早的评论
I'm running my code and I am getting an error about how the vector must be the same length. Does anyone have advice because I thought the vectors were fillled to the same length?
ntrails = 20;
N_run = zeros(ntrails,1);
BC = [5,-5,-5,5];
for trail = 1:1:ntrails
xA = -5; xAK = xA;
yA= 0; yAK = yA;
xB = 5; xBK = xB;
yB = 0; yBK = yB;
nsteps = 1000;
collision_flag = 0; k = 0;
while collision_flag == 0 && k < nsteps
[xAKp1, yAKP1] = RandWalk_2D(xAK,yAK,BC);
[xBKp1, yBKP1] = RandWalk_2D(xBK,yBK,BC);
xAK_val = [xAK-.5, xAK + .5, xAK + .5, xAK -.5];
yAK_val = [yAK-.5, yAK + .5, yAK + .5, yAK - .5];
xAKp1_val = [xAKp1-.5, xAKp1 + .5, xAKp1 + .5, xAKp1 -.5];
yAKp1_val = [yAKp1-.5, yAKp1 + .5, yAKp1 + .5, yAKp1 - .5];
xBK_val = [xBK-.5, xBK + .5, xBK + .5, xBK -.5];
yBK_val = [yBK-.5, yBK + .5, yBK + .5, yBK - .5];
xBKp1_val = [xBKp1-.5, xBKp1 + .5, xBKp1 + .5, xBKp1 -.5];
yBKp1_val = [yBKp1-.5, yBKp1 + .5, yBKp1 + .5, yBKp1 - .5];
figure(1)
hold on
xlim([-5.5,5.5,])
ylim([-5.5,5.5,])
fill(xAK_val,yAK_val,'r') %current step A
fill(xAKp1_val, yAKp1_val, 'b')%next step for A
fill(xBK_val,yBK_val,'r') %current step B
fill(xBKp1_val, yBKp1_val, 'b')%next step for B
hold off
xAK = xAKp1; yAK = yAKp1;
xBK = xBKP1; yBK = yBKp1;
k = k+1;
if xAK == xBK && yAK == yBK
collision_flag = 1;
N_run(trail) = k;
end
end
end
medval = median(N_run)
function [x,y] = RandWalk_2D(x0,y0,BC)
r = rand;
if r<0.2
x = x0;
y = y0+1;
if y >= BC(1); y = BC(1);
end
else if 0.2 < r && r <= 0.4;
x = x0;
y = y0-1;
if y <= BC(2);
y = BC(2);
end
elseif 0.4< r && r<=0.6
x = x0 - 1;
y = y0;
if x<= BC(3); x = BC(3)
end
elseif 0.6 < r && r <= 0.8;
x = x0+1; y = y0;
if x >= BC(4); x = BC(4);
end
elseif 0.8<r
x = x0; y = y0;
end
end
end
1 个评论
Mario Malic
2020-7-26
The code is not working. Meanwhile, you can call the variables in the command window that report the error and check what's the issue. Also, post the error in the future.
Undefined function or variable 'yAKp1'.
Error in Marios (line 19)
yAKp1_val = [yAKp1-.5, yAKp1 + .5, yAKp1 + .5, yAKp1 - .5];
采纳的回答
更多回答(0 个)
类别
在 帮助中心 和 File Exchange 中查找有关 Debugging and Analysis 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!