finding minimum value in Quanterion matrix

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FIR 2012-12-21

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采纳的回答： Matt J

I have a 386x514 quaternion array,in this please tell how to find the minimum value of that matrix

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FIR 2012-12-21

My form is 384x512 pure quaternion array with uint8 components

if i use min i get error

Undefined function or method 'min' for input arguments of type 'quaternion'.

Matt J 2012-12-21

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FIR Commented:

i downloaded [the quaternion] tool box from here

http://sourceforge.net/projects/qtfm/

FIR Commented:

Sorry Matt my code [which doesn't work] is

    A=imreadq('peppers.png');
    T=65;
    for i=2:6
        for j=2:6
            q= A(i-1:i+1,j-1:j+1);
            [minsum, minidx] = min( sum(abs(bsxfun(@minus, q(:), q(:).'))) );
            qVFM = q(minidx);
              V1=an equation
              V2=an equation
              S=min([V1 V1]);
              if S>T
                  THE CENTRE PIXEL IS REPLACED BY qVFM %%%%3x3 matrix
              else
                  THE CENTRE PIXEL IS not REPLACED BY qVFM%%%%3x3 matrix
              end
          end
      end

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采纳的回答

Matt J 2012-12-21

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编辑：Matt J 2012-12-21

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BSXFUN isn't overloaded well in the quaternion toolbox that you're using. Here is a workaround

 q= convert(A(i-1:i+1,j-1:j+1),'single');
[minsum, minidx] = min( sum(abs(   repmat(q(:),1,9)-repmat(q(:).',9,1)  ) ));

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Matt J 2012-12-22

Isn't the center pixel A(i,j)? If so, do A(i,j)=whatever.

Walter Roberson 2012-12-22

Or, since that would affect the computations as you slid the window, create a second array and set the pixels in it -- as I showed you in one of your previous questions.

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