finding minimum value in Quanterion matrix

2 次查看（过去 30 天）
FIR
FIR 2012-12-21
I have a 386x514 quaternion array,in this please tell how to find the minimum value of that matrix
  3 个评论
显示 1更早的评论
FIR
FIR 2012-12-21
My form is 384x512 pure quaternion array with uint8 components
if i use min i get error
Undefined function or method 'min' for input arguments of type 'quaternion'.
Matt J
Matt J 2012-12-21
FIR Commented:
i downloaded [the quaternion] tool box from here
http://sourceforge.net/projects/qtfm/
FIR Commented:
Sorry Matt my code [which doesn't work] is
A=imreadq('peppers.png');
T=65;
for i=2:6
for j=2:6
q= A(i-1:i+1,j-1:j+1);
[minsum, minidx] = min( sum(abs(bsxfun(@minus, q(:), q(:).'))) );
qVFM = q(minidx);
V1=an equation
V2=an equation
S=min([V1 V1]);
if S>T
THE CENTRE PIXEL IS REPLACED BY qVFM %%%%3x3 matrix
else
THE CENTRE PIXEL IS not REPLACED BY qVFM%%%%3x3 matrix
end
end
end

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Matt J
Matt J 2012-12-21
编辑：Matt J 2012-12-21
BSXFUN isn't overloaded well in the quaternion toolbox that you're using. Here is a workaround
q= convert(A(i-1:i+1,j-1:j+1),'single');
[minsum, minidx] = min( sum(abs( repmat(q(:),1,9)-repmat(q(:).',9,1) ) ));
  9 个评论
显示 7更早的评论
Matt J
Matt J 2012-12-22
Isn't the center pixel A(i,j)? If so, do A(i,j)=whatever.
Walter Roberson
Walter Roberson 2012-12-22
Or, since that would affect the computations as you slid the window, create a second array and set the pixels in it -- as I showed you in one of your previous questions.

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Matched Filter and Ambiguity Function 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by