double summation. for loop

1 次查看（过去 30 天）
Saranika Das
Saranika Das 2020-7-29
评论： Rik 2020-8-4
N = 16;
h=1/N;
b=(2/(N*200))^0.5;
c=(250000*h/(N*200))^0.5;
L=1;
xt=7/N;
syms xp m n
Fi=-((h*(b^2)/(c^2))^2)*(cos((2*m-1)*pi*xt/(2*L))*cos((2*n-1)*pi*xt/(2*L)))*((sin((2*m-1)*pi*xp*h/(2*L))*sin((2*n-1)*pi*xp*h/(2*L)))+(sin((2*m-1)*pi*xp*h/(2*L))*sin((2*n-1)*pi*xp*h/(2*L))))/(((2*m-1)*pi/(2*L))*((2*n-1)*pi/(2*L)));
for xp = 1:N
for m=1:N-1
for n=m+1:N
z(m) =subs(Bi);
z1(n) =sum(subs((z)));
end
end
B(xp)=subs(sum(z1));
end
disp(double(B'));
  5 个评论
显示 3更早的评论
Saranika Das
Saranika Das 2020-8-4
Sir I am using symbolic variables to generalize the code. I need to find the values for xp and see its variation using a plot
Rik
Rik 2020-8-4
If you need to find the values of xp, what values of F do you have?

请先登录，再进行评论。

请先登录，再回答此问题。

回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Common Operations 的更多信息

标签

产品


版本

R2013a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by