Angle between two lines in frontal plane
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Hello,
Would you please assist me to find the angle between two points? The following lines are a part of an old program and I have to use it for my project.
In the frontal plane, there is comY (value of com on Y coordinate in fig1) and comZ ( value of com on Z coordinate in fig1 ) as well as COPY ( value of COP on Y coordinate in fig1 ) and COPZ ( value of COM on Z coordinate in fig1 ). The following lines calculate the slope between the two points
v_1Fro = [comZ,comY] - [COPZ,COPY];
slopeV_1Fron = (COPY - comY) ./ (COPZ - comZ);
The following lines calculate the slope between [COPY,COPZ] and another point which is perpendicular to this point [(COPY+100), COPZ]:
v_2Fron = [COPZ,(COPY+100)] - [COPZ,COPY];
slopeV_2Fron = (COPY - (COPY+100)) ./ (COPZ - COPZ);
This part: (COPZ - COPZ) does not work because it is always "0"! Is it normal and correct? As I am a beginner, I am not confident and I wanted to ask you as professionals to know your ideas.
The following calculates the angle between these slopes:
ThetaFron = atan(slopeV_1Fron) - atan(slopeV_2Fron);
Would you please confirm that the lines calculate the angle between two lines, as is shown in fig1? If no, please introduce me the best way.
Thank you so much.
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Vladimir Sovkov
2020-7-30
1 个投票
If, as it looks in the figure, (...Y) are the verticle coordinates and (...Z) are the horizontal coordinates, then the basic geometry is 
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