How to revolve 1D vector into a 2D matrix with sub-pixel interpolation?

12 次查看（过去 30 天）
Matt Southwick
Matt Southwick 2020-7-30
回答： Matt Southwick 2020-7-30
Hi,
I would like take a 1D vector and revlove it about an endpoint to create a 2D image with the values of the original vector interpolated over the rotation.
This seems like a surface of revolution problem.
I tried to do this using the 2D filter tool ftrans2() as below:
N = 111;
a = zeros(N,1);
center = round(N/2);
offset = 30;
a([center-offset,center+offset]) = .25;
a([center-offset+1,center+offset-1]) = .75;
plot(a)
h = ftrans2(a');
imagesc(h)
Thanks for the help
Matt

请先登录，再回答此问题。

采纳的回答

Matt Southwick
Matt Southwick 2020-7-30
Found a solution from Pau GALLES in another thread
[rx,ry]=meshgrid( -order/2:order/2 , -order/2:order/2 );
r = hypot( rx , ry );
halfb = b((length(b)-1)/2 + 1 : end );
vq = interp1( 0:(length(halfb)-1) , halfb , r(:) , 'linear' , 0 );
W=r; W(:)=vq;
https://www.mathworks.com/matlabcentral/answers/69071-creating-a-solid-surface-of-revolution-from-discrete-data#answer_247469
Thank you Pau.
Also works for 1D curve to 3D as follows
[rx,ry,rz]=meshgrid( -order/2:order/2 , -order/2:order/2,-order/2:order/2 );
r = sqrt(rx.^2+ry.^2+rz.^2);
halfb = b((length(b)-1)/2 + 1 : end );
vq = interp1( 0:(length(halfb)-1) , halfb , r(:) , 'linear' , 0 );
W=r; W(:)=vq;

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Geometric Transformation and Image Registration 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by