Reshape n-th dimension of an array

1 次查看（过去 30 天）
zdarova_koresh
zdarova_koresh 2020-8-7
评论： zdarova_koresh 2020-8-7
I have an 285x51xn array. I need to reshape it in 3rd (n) dimension. Essentialy, I want to rotate all layers of 285x51 matrix 90 degrees and flip them upside down and then save as 285x51xn array.
I have written the following code but it gives an error that dimensions mismath. I feel there is a problem with indexing.
for k = 1:length(test(1, 1, :))
test(:,:,k)=rot90(test(:,:,k));
test(:,:,k)=flipud(test(:,:,k))
end
Please, correct me.

请先登录，再回答此问题。

采纳的回答

Bruno Luong
Bruno Luong 2020-8-7
编辑：Bruno Luong 2020-8-7
You operation makes the array changing its size, you can't use for-loop to store the rotated page in the SAME arrray.
And btw fllipupd(rot90(...)) is simply exchange the first 2 dimensions
test = permute(test,[2 1 3]);

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Resizing and Reshaping Matrices 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by