how can we do "8-coarse division of RGB color space" for dominant color extraction?

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preet 2012-12-31

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https://ww2.mathworks.cn/matlabcentral/answers/57680-how-can-we-do-8-coarse-division-of-rgb-color-space-for-dominant-color-extraction

this is basically for quantized color.

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Image Analyst 2012-12-31

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Try rgb2ind() or this kmeans example

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Image Analyst 2012-12-31

It looks like the FAQ applies here: http://matlab.wikia.com/wiki/FAQ#Can_you_program_up_the_algorithm_in_this_article_for_me_and_explain_it_to_me.3F, though it looks somewhat interesting so if I can find the time today or tomorrow maybe I can read the paper.

preet 2012-12-31

编辑：Image Analyst 2012-12-31

i appreciate if u do for me... happy new year..

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Walter Roberson 2012-12-31

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https://ww2.mathworks.cn/matlabcentral/answers/57680-how-can-we-do-8-coarse-division-of-rgb-color-space-for-dominant-color-extraction#answer_69817

在 MATLAB Online 中打开

dImage = im2double(YourImage);
binned_image = round(dImage);
quadrant_num = binned_image(:,:,1) * 4 + binned_image(:,:,2) * 2 + binned_image(:,:,1);

quadrant 0 would be (low red, low blue, low green), quadrant 1 would be (low red, low blue, high green), quadrant 2 would be (low red, high blue, low green), and so on up to quadrant 7 as (high red, high blue, high green)

You might want to add 1 to the quadrant number, if you want to use it as an index.

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preet 2013-1-1

i said i need the result like rgb2ind()..

Walter Roberson 2013-1-1

在 MATLAB Online 中打开

Okay, here it is:

dImage = im2double(YourImage);
binned_image = round(dImage);
quadrant_num = uint8( binned_image(:,:,1) * 4 + binned_image(:,:,2) * 2 +   binned_image(:,:,1) );

quadrant_num will now be exactly like rgb2ind() in that it will return a 2D array of uint8() values, each of which is an "ind". Keep in mind that exactly like rgb2ind(), the value 0 represents the first color in the color map, and 1 represents the second color, and so on.

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