how can we do "8-coarse division of RGB color space" for dominant color extraction?

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preet
preet 2012-12-31
this is basically for quantized color.

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回答（2 个）

Image Analyst
Image Analyst 2012-12-31
Try rgb2ind() or this kmeans example
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Walter Roberson
Walter Roberson 2012-12-31
dImage = im2double(YourImage);
binned_image = round(dImage);
quadrant_num = binned_image(:,:,1) * 4 + binned_image(:,:,2) * 2 + binned_image(:,:,1);
quadrant 0 would be (low red, low blue, low green), quadrant 1 would be (low red, low blue, high green), quadrant 2 would be (low red, high blue, low green), and so on up to quadrant 7 as (high red, high blue, high green)
You might want to add 1 to the quadrant number, if you want to use it as an index.
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Walter Roberson
Walter Roberson 2013-1-1
Okay, here it is:
dImage = im2double(YourImage);
binned_image = round(dImage);
quadrant_num = uint8( binned_image(:,:,1) * 4 + binned_image(:,:,2) * 2 + binned_image(:,:,1) );
quadrant_num will now be exactly like rgb2ind() in that it will return a 2D array of uint8() values, each of which is an "ind". Keep in mind that exactly like rgb2ind(), the value 0 represents the first color in the color map, and 1 represents the second color, and so on.

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