Error::Assignment has more non-singleton rhs dimensions than non-singleton subscripts
显示 更早的评论
I m trying the following code :
for o=1:n x=length(find(cell2mat(mi(1,o)))); m(1,o)=[m(1,o),x]; end
and I get this error.mi and m are cell arrays and both has dimensions of (1xn)
The above code has worked for a similar assignment but a different function on line 2. please help. Thanks!
2 个评论
Just re-formatting this for better readability,
for j=1:n
x=length(find(cell2mat(mi(1,j))));
m(1,j)=[m(1,j),x];
end
Tripti Malviya
2013-1-5
采纳的回答
Instead of
m(1,j)=[m(1,j),x];
I think you meant
m{1,j} = x;
Otherwise, clarify what you want m{1,j} to contain.
4 个评论
Tripti Malviya
2013-1-5
I'm skeptical that you've really done
m{1,j} = x;
I suspect what you've really done is used brackets '()' instead of braces '{}'
m(1,j) = x;
The latter would definitely explain the 'Conversion to cell' error.
Tripti Malviya
2013-1-5
That does make more sense. Even better would be to do
for o=1:n
m(1,o)=nnz(mi{1,o});
end
Or, if you want to hide the for-loop
m=cellfun(@nnz,mi);
更多回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Functions 的更多信息
产品
2013-1-5
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
