Counting occurrence of keys and values for Containers.Map in another Containers.Map

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How it is possible to count occurrence of keys and values of Containers.Map A in B?
A = containers.Map({1026,1033,1038,1042},...
{[605.914,48.521],[490.6086 23.7932],[257.558,67.625],[439.090,225.924]});
B = containers.Map({1025,1026,1028,1029,1031,1033,1035,1037,1038},...
{[397.494,168.066],[605.914,48.521],[295.712,176.770],[226.249,209.288],...
[52.573,278.126],[490.6086 23.7932],[50.747,213.198],[38.992,4.417],[257.558,67.625]});
Thank you!!

采纳的回答

J. Alex Lee
J. Alex Lee 2020-8-18
Just considering the keys, you can use ismember (though I'm not sure why there's a limitation that cells must be cell arrays of character vectors, and can't be numbers..)
[mask] = ismember(cell2mat(B.keys),cell2mat(A.keys))
cnt = sum(mask)
[mask] = ismember(B.keys,A.keys)
If you need to check if values are the same, you can iterate through the matched keys and use isequal()
  2 个评论
Ravindra
Ravindra 2020-8-18
Thank you Lee!!
The first two line works. The following command gives error :
[mask] = ismember(B.keys,A.keys)
Error using cell/ismember (line 34)
Input A of class cell and input B of class cell must be cell
arrays of character vectors, unless one is a character
vector.
I tried another way as well....
C = cell2mat(A.keys)
idx = find(cell2mat(B.keys)== C(1))
idx = find(cell2mat(B.keys)== C(2))
idx = find(cell2mat(B.keys)== C(4))
Thank you again!!
J. Alex Lee
J. Alex Lee 2020-8-19
Yes, sorry should have clarified the last line doesn't work, but seems like a silly limitation by TMW to me. Glad it helps!

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