GUI, make a handle disappear

12 次查看(过去 30 天)
Hey, I am MArc and I have a question about a GUI. have this GUI interface:
I want to achieve that when clicking both pink clickboxes I want to make all the red handles disappear. I tried with a function using the button 2, like this:
methods (Access = private)
function Button2Pushed(app, event,handles)
value1= get(handles.PRETESSATRECTECheckBox,'Value')==0;
value2= get(handles.PRETESSATENCASTAMENTCheckBox,'Value')==0;
value3= get(handles.PRETESSATPARABLICCheckBox,'Value')==1;
value4= get(handles.ntramsCheckBox,'Value')==1;
if value1 && value2 && value3&& value4
set(handles.LmEditField_3, 'Visible', 'off');
set(handles.readelaseccim2EditField_2, 'Visible', 'off');
set(handles.LNmEditField_2, 'Visible', 'off');
set(handles.Inrciam4EditField_2, 'Visible', 'off');
set(handles.AmpladadelaseccimEditField_2, 'Visible', 'off');
set(handles.ncordonsEditField_2, 'Visible', 'off');
set(handles.Sigma_uMPaEditField_2, 'Visible', 'off');
set(handles.Sigma_yMPaEditField_2, 'Visible', 'off');
set(handles.CargapermanentKNm2EditField, 'Visible', 'off');
set(handles.SobrecargavariableKNm2EditField, 'Visible', 'off');
set(handles.SobrecargavariableKNEditField, 'Visible', 'off');
set(handles.PuntualKNEditField, 'Visible', 'off');
set(handlesD_vainammEditField, 'Visible', 'off');
else
set(handles.LmEditField_3, 'Visible', 'on');
end
end
end
But it does not work, it does nothing. I would like some advice, thank you
  6 个评论
Marc Martinez Maestre
Yes, maybe is that it is not called, but I do not understand why, because it is located at the top of the code, previous to anything.
This is part of the code:
methods (Access = private)
function CheckBoxValueChanged(app, event)
% Get values of all checkboxes
cb(1) = app.PRETESSATPARABLICCheckBox.Value;
cb(2) = app.ntramsCheckBox.Value;
% Toggle the visibility flag depending on checkbox states
if all(cb)
visibleFlag = 'off';
else
visibleFlag = 'on';
end
app.LNmEditField_2.Visible = visibleFlag;
app.LmEditField_3.Visible = visibleFlag;
% etc...
end
end
% Callbacks that handle component events
methods (Access = private)
% Button pushed function: Button
function ButtonPushed(app, event)
value1= get(app.PRETESSATRECTECheckBox,'Value');
value2= get(app.PRETESSATENCASTAMENTCheckBox,'Value');
value3= get(app.PRETESSATPARABLICCheckBox,'Value');
value4= get(app.ntramsCheckBox,'Value');
if value1==0 && value2==0 && value3==0
msgbox(sprintf('Enter a valid selection'),'Error','error');
end
if value1==1
%---------------------------------------------------------------------------------------------------------------------------------------------------%
%-------------------------------------------------------------------PRETESSAT RECTE-----------------------------------------------------------------%
%---------------------------------------------------------------------------------------------------------------------------------------------------%
% Lllegir els valors previs
h_var = app.hcmEditField.Value;
end
end
So, it should be called, shouldn't it?
Rik
Rik 2020-8-20
Change this
function CheckBoxValueChanged(app, event)
to this
function CheckBoxValueChanged(app, event)
uiwait(msgbox('the function was called'));
Then you know for sure if it is called or not.

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采纳的回答

Adam Danz
Adam Danz 2020-8-19
"I want to achieve that when clicking both pink clickboxes I want to make all the red handles disappear. "
The function you shared requires two checkboxes to be not-selected and two to be selected. That doesn't match your description.
Also, the checkbox detection needs to happen when any of the applicable checkboxes are toggled. If the detection only exists in 1 checkbox callback, toggling the other one will have no effect.
To avoid having 2 copies of the same code, assign the same CheckBoxValueChanged function to each applicable checkbox.
function CheckBoxValueChanged(app, event)
% Get values of all checkboxes
cb(1) = app.CheckBox.Value;
cb(2) = app.CheckBox2.Value;
% Toggle the visibility flag depending on checkbox states
if all(cb)
visibleFlag = 'off';
else
visibleFlag = 'on';
end
app.LNmEditField_2.Visible = visibleFlag;
app.LmEditField_3.Visible = visibleFlag;
% etc...
end
  5 个评论
Adam Danz
Adam Danz 2020-8-20
Here are the steps you need to take to fix the proble.
1) Add ValueChangeFcn callback function to one of the check boxes. Right-click the checkbox to show the menu you see below. That will add a new function in Code View.
2) Set up the function I provided in my answer. Note that the function in my answer is a demo. You'll need to understand what's going on in that function and adapt it to your needs. If you have specific questions with that, I can help.
3) Go back to Design Mode and right-click the other checkbox. This time, instead of adding a new ValueChangeFcn, you're going to select an existing callback, and select the function you just added.
4) Clean up the old stuff in your code.
To test it, I used the first 2 checkboxes to turn off/on a few components in the right column.
Marc Martinez Maestre
Thank you soo much, really awesome answer and really guided. Thank you

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更多回答(1 个)

Ruger28
Ruger28 2020-8-19
As suggested above, make all of the items you would like to "disappear" (turn visibility off) by lumping them together in a single handle. Below is a quick example I threw together.
% in the opening function before gui is made visible
handles.MyEditBoxes = [handles.edit1,handles.edit2,handles.edit3,handles.edit4,handles.edit5];
Then for your pushbutton, get the values of the two checkboxes, and AND them.
% --- Executes on button press in pushbutton1.
function pushbutton1_Callback(hObject, eventdata, handles)
value1 = get(handles.checkbox1,'Value');
value2 = get(handles.checkbox2,'Value');
if value1 && value2
set(handles.MyEditBoxes,'Visible','off');
else
set(handles.MyEditBoxes,'Visible','on');
end
This will hide/unhide the items in MyEditBoxes.
  1 个评论
Marc Martinez Maestre
Thank you Ruger28 but, how would it be to set the visibility off only by clicking two checkboxes?
Thank you

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