Error using cellstr. Shows error for element that doesn't exist.

Question

Jannat Manchanda 2020-8-19

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/581828-error-using-cellstr-shows-error-for-element-that-doesn-t-exist

编辑： Fangjun Jiang 2020-8-20

I am getting the following error:

Error using cellstr (line 44) Element 154 is not a string scalar or character array. All elements of cell input must be string scalars or character arrays.

But the array I am trying to conver has size: [153 4]

I am trying to display the data to MATLAB Table (App Designer).

I am saving the data into a cell matrix form then converting to string to display in a table in the app.

TblAllInfo=[app.FMain',ChannelNameFinal',LocationFinal',ChannelFilter'];
app.UITableAll.Data=cellstr(TblAllInfo); 

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Answer 1

Fangjun Jiang 2020-8-19

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https://ww2.mathworks.cn/matlabcentral/answers/581828-error-using-cellstr-shows-error-for-element-that-doesn-t-exist#answer_482363

在 MATLAB Online 中打开

I can duplicate the error using this simple example. So the problem is TblAllInfo{1,2}. It is the 154th element. It is not a char array.

a =
  3×2 cell array
    {'a'}    {[1]}
    {'a'}    {[2]}
    {'c'}    {[3]}
>> cellstr(a)
Error using cellstr (line 44)
Element 4 is not a string scalar or character array. All elements of cell input must be string
scalars or character arrays. 

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Jannat Manchanda 2020-8-19

Yes, exactly this. How to resolve it ?

Fangjun Jiang 2020-8-20

编辑：Fangjun Jiang 2020-8-20

The method depends on the data types. Why don't you show some example data?

In my example data, you could use cellstr(string(a))

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Answer 2

Jannat Manchanda 2020-8-19

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/581828-error-using-cellstr-shows-error-for-element-that-doesn-t-exist#answer_482369

在 MATLAB Online 中打开

For now I have added the following code, so that I can proceed with my work. If anyone has any better answers. TIA :)

for i=1:length(TblAllInfo)
        Data1{i}=string(TblAllInfo(i,:));
        Data2{i,:}=cellstr(Data1{1,i});
        Data3(i,:)=Data2{i};
    end
    
    app.UITableAll.Data=Data3;