find expression within {}
6 次查看(过去 30 天)
显示 更早的评论
Hello all,
i have to fin {i++;} from the below expression using regexp.can some one help me out?
x = [task_queue[i] > 0 && i<NUM_FLOOR]{i++;}/{a =1;};
i tired using the below regexp
regexp(x,'[^/]\s*{.*}','match')
output : ']{i++;}/{a =1;}'
Thanks,
Ajay
2 个评论
Rik
2020-8-20
Although you can do it with regexp, why would you? strfind will do the job here. What do you want to do with the result?
采纳的回答
Rik
2020-8-20
You were close: you forgot to make the expression lazy, and you forgot you included the close bracket from the sting when excluding the / matched part.
str='x = [task_queue[i] > 0 && i<NUM_FLOOR]{i++;}/{a =1;};';
a=regexp(str,'[^/]({.*?})','tokens');
a{1}
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 String Parsing 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!