find expression within {}

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Hello all,

i have to fin {i++;} from the below expression using regexp.can some one help me out?

x = [task_queue[i] > 0 && i<NUM_FLOOR]{i++;}/{a =1;};

i tired using the below regexp

regexp(x,'[^/]\s*{.*}','match')

output : ']{i++;}/{a =1;}'

Thanks,

Ajay

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Rik 2020-8-20

Although you can do it with regexp, why would you? strfind will do the job here. What do you want to do with the result?

Ajay krishna Vasanthakumar 2020-8-20

i just want to to pick the chars inside {.*}.i dont want to pick /{.*} and append some varibales using regexprep.

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Answer 1

Rik 2020-8-20

在 MATLAB Online 中打开

0 个投票

You were close: you forgot to make the expression lazy, and you forgot you included the close bracket from the sting when excluding the / matched part.

str='x = [task_queue[i] > 0 && i<NUM_FLOOR]{i++;}/{a =1;};';
a=regexp(str,'[^/]({.*?})','tokens');
a{1}

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Ajay krishna Vasanthakumar 2020-8-20

编辑：Ajay krishna Vasanthakumar 2020-8-20

Thanks alot rik :)

i did a small correction to the expression

str='x = [task_queue[i] > 0 && i<NUM_FLOOR]{i++;}/{a =1;};';

a=regexp(str,'(?<!/\s*){.*?}','match');

a{1}

just to make sure the before letter is not followed by /.

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