Removing time from datetime

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AA
AA 2020-8-23
编辑： Steven Lord 2020-8-23
Hi,
I have a datetime array in the following format i.e. 31-Dec-2019 08:00:00. I just want to remove the time component from the datetime so that I get 31-Dec-2019. Any ideas

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采纳的回答

Steven Lord
Steven Lord 2020-8-23
编辑：Steven Lord 2020-8-23
If you want to change how it is displayed, change the Format property.
>> dt = datetime('now')
dt =
datetime
23-Aug-2020 15:43:06
>> dt.Format = 'dd-MMM-yyyy'
dt =
datetime
23-Aug-2020
If you want to change what's stored and used for calculation, dateshift the datetime to the start of the day.
>> dt2 = dateshift(dt, 'start', 'day');
>> dt - dt2
ans =
duration
15:43:06

更多回答（1 个）

Star Strider
Star Strider 2020-8-23
Try this:
dt = '31-Dec-2019 08:00:00';
Out = datetime(dt, 'InputFormat','dd-MMM-yyyy HH:mm:ss', 'Format','dd-MMM-yyyy')
producing:
Out =
datetime
31-Dec-2019
.

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