When i execute function my matlab is being struck; is there any wrong with this simple code???

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nayana 2013-1-9

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     In the following arr is a array(1-d) in which each row has three columns of 
  x-co-ordinate , y-co-ordinate and intensity values ;
  m*n is the required size of output image ie fgt here.
  In the code initially i have simply assigned all values to 65539(which is not  in range of uint16)
function [fgt]= reconstruct ( arr,m,n)
  fgt=zeros(m,n);
  fgt(:,:)=65539; % 
  l=size(arr,2)-2;
  for i=1:l
      fgt(arr(i),arr(i+1))=arr(i+2);
      i=i+3;
  end
  for i=1:m
      for j=1:n
          if(fgt(i,j)==65539)
              fgt(i,j)=0;
          end
      end
  end

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Azzi Abdelmalek 2013-1-9

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If arr is a real array, then there will be a problem with fgt(arr(i),arr(i+1))

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Azzi Abdelmalek 2013-1-9

在 MATLAB Online 中打开

I tested your code, there is no problem,

arr=randi(10,8,3)
m=8,n=3;
fgt=zeros(m,n);
fgt(:,:)=65539; % 
l=size(arr,2)-2;
for i=1:l
    fgt(arr(i),arr(i+1))=arr(i+2);
    i=i+3;
end
for i=1:m
    for j=1:n
        if(fgt(i,j)==65539)
            fgt(i,j)=0;
        end
    end
end

nayana 2013-1-9

Thank you for your immediate response, maybe there's something wrong with my mat lab software.I will re install and see

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Walter Roberson 2013-1-9

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在 MATLAB Online 中打开

Please do not use "l" as a variable name: it is too easy to confuse it with "1".

You have

for i=1:l
  i=i+3
end

changing a loop variable inside of the "for" loop has an effect only until the beginning of the next loop iteration. If you want to increment by 3's, then use

for i = 1 : 3 : l