Making combinations using random number generators

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Chris Dan
Chris Dan 2020-8-28
评论： Rafael Hernandez-Walls 2020-8-30
Hello,
I have this vector
x0 = [1;88;88;2;2;2;2;2;-88;2]
Right now I change the values in this vector manually making combinations, I am looking for a random number generator which will generate combinations of numbers on these 10 slots, like a combination of 10 numbers from 0 till infinity, numbers can be decimals or integers as well or a combination of both
x0 = [x1;x2;x3;x4;x5;x6;x7;x8;x9;x10]
Does anyone knows how it can be done?
I have to use this vector elsewhere in the code...
  2 个评论
Rafael Hernandez-Walls
Rafael Hernandez-Walls 2020-8-28
In general, you can generate N random numbers in the interval (a,b) with the formula:
r = a + (b-a).*rand(N,1)
Chris Dan
Chris Dan 2020-8-28
Rafael Hernandez-Walls
Hi, how can i make it run in a loop, so at each iteration I get a new combination

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采纳的回答

Rafael Hernandez-Walls
N=input('give me number of random elements:');
a=input('lower limit of the numbers to generate:');
b=input('upper limit of the numbers to generate:');
M=input('How many arrangements do you want to generate ?:');
r=zeros(N,M);
for k=1:M
r(:,k)=a+(b-a)*rand(N,1);
end
  1 个评论
Rafael Hernandez-Walls
Rafael Hernandez-Walls 2020-8-30
oops!!!!
N=input('give me number of random elements:');
a=input('lower limit of the numbers to generate:');
b=input('upper limit of the numbers to generate:');
M=input('How many arrangements do you want to generate ?:');
r=zeros(N,M);
r(:,1)=a+(b-a)*rand(N,1);
for k=2:M
a=randperm(N);
r(:,k)=r(a,1);
end

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更多回答（1 个）

Steven Lord
Steven Lord 2020-8-28
If you want to draw with replacement use randi to generate numbers between 1 and the numel of the array you want to sample. Use those as linear indices into the array.
If you want to draw without replacement use randperm to generate the linear indices.

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