How to replace a column vector in matrix

A = [1 -4 1;4 -1 2;2 2 -3]
B = [6;-1;-20]
I want to replace part of matrx A i.e (1 -4 1) with B.
How can I do this?
Thank you for your help.

2 个评论

"How can I do this? "
Basic indexing (just the the introductory tutorials show):
>> A = [1,-4,1;4,-1,2;2,2,-3]
A =
1 -4 1
4 -1 2
2 2 -3
>> B = [6;-1;-20];
>> A(1,:) = B
A =
6 -1 -20
4 -1 2
2 2 -3
how do you set the name of the new matrix , instead of A can you change it to Ax without changing the name of the original matrix. Please demosntrate thank you

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 采纳的回答

A = [1 -4 1;4 -1 2;2 2 -3]
B = [6;-1;-20]
B=B'
A(1,:)=B'

4 个评论

You don't actually need to do any transposing. Just using B directly works, even though B is a column vector and you are assigning it to a row:
A(1,:) = B;
how do you set the name of the new matrix , instead of A can you change it to Ax without changing the name of the original matrix. Please demosntrate thank you
If you want changed matrix Ax without changing matrix A, just copy the contents of matrix A over to a new matrix Ax, then do the same replacement.
A = [1 -4 1;4 -1 2;2 2 -3]
B = [6;-1;-20]
B = B'
Ax = A
Ax(1,:) = B'

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