rounding down using floor
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so im using:
floor(10^decimal*(total/AVERAGE_COUNT))/10^decimal;
where:
decimal = 4, AVERAGE_COUNT = 9, total = 8.9289
this entry gives me 0.9920, however the answer should be 0.9921
furthermore, when I just do
total/AVERAGE_COUNT;
it gives me 0.9921 which is correct but i need to use the floor function for the rest of my data.
how do i get around this
3 个评论
Walter Roberson
2020-9-1
Which MATLAB release are you using, and which operating system?
I get 0.9921 on R2020a on Mac
marcus peixoto
2020-9-1
per isakson
2020-9-1
On my R2018b, Win10 this script
%%
format long
decimal = 4; AVERAGE_COUNT = 9; total = 8.9289;
x = floor(10^decimal*(total/AVERAGE_COUNT))/10^decimal
outputs
x =
0.992100000000000
>>
回答（1 个）
Dana
2020-9-1
0 个投票
I'm on R2020a on Windows 10 and I also get 0.9921.
Is it possible that total does not equal exactly 8.9289? For example, if total actually equals 8.92889 (which would usually display as 8.9289 in the command window), then you'll end up with 0.9920.
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2020-9-1
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