How do I maintain my array size (or dimensions) when I run it through a nested for loop?

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NA
NA 2020-9-1
评论： NA 2020-9-1
Hi All,
I have an array, 'data' (5x16x2), that I have shifted to the left (by 1 column) and zero-padded the right accordingly. However, when I run my variable through a nested for loop, my 3d array gets transformed to 2d (5x32). I'm facing some trouble trying to figure out how to maintain my array size as I run it through the nested for loop. I essentially want my 'dataShift' varible to be the same size as my 'data' variable (5x16x2).
My code looks like this:
%dummy data
for ii = 1:2
for i=1:16
data(:,i,ii)=i(:,:);
end
end
%constant variables
sink = 8;
layerIV = 7;
shift = abs(layerIV - sink);
%shift data
for ii = 1:2
for ch = 1:16
if sink > layerIV
dataShift = [data(:, shift+1:end), zeros(size(data,1),shift)];
end
end
end
I thought that perhaps the following might work:
dataShift(:,ch,ii) = [data(:, shift+1:end), zeros(size(data,1),shift)];
But I get the following error: "Unable to perform assignment because the size of the left side is 1-by-1 and the size of the right side is 1-by-32."
Would really appreciate any help.

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采纳的回答

Dana
Dana 2020-9-1
You have 3-D arrays but are only using 2-D indexing (e.g., data(:, shift+1:end) only has two indices, even though data is a 3-D array). That's going to give you unexpected results. Also, your dummy data vector doesn't have 5 rows, just 1, which I'm assuming is a mistake.
I'm not entirely clear on exactly what you're after here, but does this give the desired result?
data = repmat(1:16,5,1,2); % better way to create your dummy data
%constant variables
sink = 8;
layerIV = 7;
shift = abs(layerIV - sink);
dataShift = [data(:,shift+1:end,:),zeros(size(data,1),shift,size(data,3))];

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