Error using cat: Dimensions of matrices being concatenated are not consistent.

Question

pink flower 2020-9-3

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评论： Walter Roberson 2020-9-4

Hello!

I have this program that, at the end, I need to assemble a matrix with 5 columns: var1, var2, var3, var4 and hh. However I get this error: Error using cat Dimensions of matrices being concatenated are not consistent.

clear all;
close all;
str='/home/pink/Documents';
folder_name = uigetdir(str);
files = dir(fullfile(folder_name,'*.dat'));
curr_folder=pwd;
cd(folder_name);
for i = 1:length(files); 
    fileID = fopen(files(i).name); 
    ref = fread(fileID,[500 500], 'float32'); 
    teste = find(ref<0); 
    ref(teste) = NaN;
    rot = rot90(ref);
    latitude = [-3.63965:-0.00898:-8.12601]; 
    longitude = [-37.5098:0.00906:-32.9831]; 
    L1 = 1; 
    L2 = 500;
    for LL = L1:L2;
      array_latitude (1:500,LL) = latitude;
    end
    array_lat = array_latitude(1:500,1:500);
    array_lat;
    for Lll = L1:L2;
      array_longitude(Lll,1:500) = longitude;
    end
    array_long = array_longitude(1:500,1:500);
    array_long;
    var1 = find(rot>=20);
    var2 = array_lat(var1); 
    var3 = array_long(var1);
    var4 = rot(var1);
    for j = 1:length(var1); 
      name = files(i).name;
      s = strsplit(name,'_');
      km = s{3};
      alt{j,1} = km;    
    end 
    hh = cellfun(@str2double,alt);
    B = cat(2,var1,var2,var3,var4,hh);
end

The problem is in this loop. For each file that opens, I have a different size for var1 and, consequently, the size of hh should change and is not changing, so it says that the dimensions are different.

    for j = 1:length(var1); 
      name = files(i).name;
      s = strsplit(name,'_');
      km = s{3};
      alt{j,1} = km;    
    end 
    hh = cellfun(@str2double,alt);

I would like help to solve this problem.

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Answer 1

dpb 2020-9-3

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https://ww2.mathworks.cn/matlabcentral/answers/588193-error-using-cat-dimensions-of-matrices-being-concatenated-are-not-consistent#answer_489190

在 MATLAB Online 中打开

latitude = [-3.63965:-0.00898:-8.12601]; 
longitude = [-37.5098:0.00906:-32.9831]; 
str='/home/pink/Documents';
folder_name = uigetdir(str);
files = dir(fullfile(folder_name,'*.dat'));
curr_folder=pwd;
cd(folder_name);
for i = 1:length(files); 
    fileID = fopen(files(i).name); 
    ref = fread(fileID,[500 500], 'float32'); 
    ref((ref<0)=NaN;
    rot = rot90(ref);
    array_lat=repmat(latitude(500,1);
    array_long=repmat(longitude,500,1);
    ix20 = find(rot>=20);
    lat20 = array_lat(ix20); 
    long20 = array_long(ix20);
    rot20 = rot(ix20);
    hh=zeros(ix20,1);
    for j = 1:length(ix20); 
      name = files(i).name;
      s = strsplit(name,'_');
      hh(j)=str2double(s{3});
    end 
    B=cat(2,ix20,lat20,long20,rot20,hh);
end

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pink flower 2020-9-4

在 MATLAB Online 中打开

Error using zeros
Size inputs must be scalar.

Did not work! :(

Walter Roberson 2020-9-4

Right, the code should not be rotating the indices returned by find() and should not be treating the indices as a length. But that logic was copied from the original logic, so you will need to be the one to debug it.

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